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Lemur [1.5K]
3 years ago
10

Plzz help

Chemistry
1 answer:
Veronika [31]3 years ago
6 0

Answer:

22

Explanation:

5.5 mol C3H8 • (4 mol H2O / 1 mol C3H8 ) = 22 mol H2O

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A solid has a high to very high melting point, great hardness , and poor electrical conduction, this is an_______solid.
xxMikexx [17]
A solid that has a high to very high melting point, great hardness, and poor electrical conduction is an : E. Ionic solid

Ionic solid consist of oppositely charge ions. One of the example of Ionic solid is salt (NaCl)

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Alex17521 [72]
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200 feet in 30 seconds is what speed?
Rzqust [24]

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Using this balanced equation: 2 NaOH + H2SO4 —> H2O + Na2SO4
mars1129 [50]
<h3>Answer:</h3>

266.325 g

<h3>Explanation:</h3>

We are given the balanced equation;

2NaOH + H₂SO₄ → H₂O + Na₂SO₄

  • Mass of NaOH as 150 g

We are required to determine the mass of Na₂SO₄ that will be formed.

<h3>Step 1: Determine the number of moles of NaOH</h3>

Moles = Mass ÷ molar mass

Molar mass of NaOH is 40.0 g/mol

Therefore;

Moles of NaOH = 150 g ÷ 40 g/mol

                          = 3.75 moles

<h3>Step 2: Determine the number of moles of sodium sulfate formed</h3>
  • From the equation 2 moles of NaOH reacts with sulfuric acid to form 1 mole of sodium sulfate.
  • Therefore; mole ratio of NaOH : Na₂SO₄ is 2 : 1

Thus, moles of Na₂SO₄ = Moles of NaOH ÷ 2

                                      = 3.75 moles ÷ 2

                                     = 1.875 moles

<h3>Step 3: Determine the mass of Na₂SO₄ produced.</h3>

we know that;

Mass = Moles × Molar mass

Molar mass of Na₂SO₄ is 142.04 g/mol

Therefore;

Mass of Na₂SO₄ = 1.875 moles × 142.04 g/mol

                           = 266.325 g

Thus, the mass of sodium sulfate formed 266.325 g

7 0
3 years ago
Give the electron configurations for the elements given. use the noble gas core preceding for the inner electrons.
Umnica [9.8K]
Noble Gas Cores have following electronic configuration

He  =  1s²
Ne  =  [He] 2s², 2p⁶
Ar  =   [Ne] 3s², 3p⁶
Kr  =   [Ar] 4s², 4p⁶
Xe  =  [Kr] 5s², 5p⁶

Now solving for question elements,

Germanium = Ge  =  [Ar] 3d¹⁰, 4s², 4p²

Nickle = Ni  =  [Ar] 3d¹⁰, 4s²

Tunsten = W  =  [Xe] 4f¹⁴, 5d⁴, 6s²

Titanium = Ti  =  [Ar] 3d², 4s²

Iron = Fe  =  [Ar] 3d⁶, 4s²

Zinc = Zn  =  [Ar] 3d¹⁰, 4s²
6 0
3 years ago
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