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UNO [17]
3 years ago
10

Kathi starts with a number . She adds 3 to her number, then doubles the result. Finally , she subtracts 7. If she ended with 9,

what number did she start with ?
Mathematics
2 answers:
miss Akunina [59]3 years ago
8 0
The number she started with is 5.
nikklg [1K]3 years ago
5 0

Answer:  The required number is 5.

Step-by-step explanation:  Given that Kathi starts with a number, she adds 3 to her number and then doubles the result. Finally , she subtracts 7 and she ended with 9.

We are to find the number.

Let n represents the required number.

Then, according to the given information, we have

2\times(n+3)-7=9\\\\\Rightarrow 2(n+3)=9+7\\\\\Rightarrow 2(n+3)=16\\\\\Rightarrow n+3=\dfrac{16}{2}\\\\\Rightarrow n+3=8\\\\\Rightarrow n=8-3\\\\\Rightarrow n=5.

Thus, the required number is 5.

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On an alien planet with no atmosphere, acceleration due to gravity is given by g = 12m/s^2. A cannonball is launched from the or
almond37 [142]

Answer:

a) \vec r (t) = \left[(90\cdot \cos \theta)\cdot t \right]\cdot i + \left[(90\cdot \sin \theta)\cdot t -6\cdot t^{2} \right]\cdot j, b) \theta = \frac{\pi}{4}, c) y_{max} = 84.375\,m, t = 3.75\,s.

Step-by-step explanation:

a) The function in terms of time and the inital angle measured from the horizontal is:

\vec r (t) = [(v_{o}\cdot \cos \theta)\cdot t]\cdot i + \left[(v_{o}\cdot \sin \theta)\cdot t -\frac{1}{2}\cdot g \cdot t^{2} \right]\cdot j

The particular expression for the cannonball is:

\vec r (t) = \left[(90\cdot \cos \theta)\cdot t \right]\cdot i + \left[(90\cdot \sin \theta)\cdot t -6\cdot t^{2} \right]\cdot j

b) The components of the position of the cannonball before hitting the ground is:

x = (90\cdot \cos \theta)\cdot t

0 = 90\cdot \sin \theta - 6\cdot t

After a quick substitution and some algebraic and trigonometric handling, the following expression is found:

0 = 90\cdot \sin \theta - 6\cdot \left(\frac{x}{90\cdot \cos \theta}  \right)

0 = 8100\cdot \sin \theta \cdot \cos \theta - 6\cdot x

0 = 4050\cdot \sin 2\theta - 6\cdot x

6\cdot x = 4050\cdot \sin 2\theta

x = 675\cdot \sin 2\theta

The angle for a maximum horizontal distance is determined by deriving the function, equalizing the resulting formula to zero and finding the angle:

\frac{dx}{d\theta} = 1350\cdot \cos 2\theta

1350\cdot \cos 2\theta = 0

\cos 2\theta = 0

2\theta = \frac{\pi}{2}

\theta = \frac{\pi}{4}

Now, it is required to demonstrate that critical point leads to a maximum. The second derivative is:

\frac{d^{2}x}{d\theta^{2}} = -2700\cdot \sin 2\theta

\frac{d^{2}x}{d\theta^{2}} = -2700

Which demonstrates the existence of the maximum associated with the critical point found before.

c) The equation for the vertical component of position is:

y = 45\cdot t - 6\cdot t^{2}

The maximum height can be found by deriving the previous expression, which is equalized to zero and critical values are found afterwards:

\frac{dy}{dt} = 45 - 12\cdot t

45-12\cdot t = 0

t = \frac{45}{12}

t = 3.75\,s

Now, the second derivative is used to check if such solution leads to a maximum:

\frac{d^{2}y}{dt^{2}} = -12

Which demonstrates the assumption.

The maximum height reached by the cannonball is:

y_{max} = 45\cdot (3.75\,s)-6\cdot (3.75\,s)^{2}

y_{max} = 84.375\,m

7 0
3 years ago
triangle abc is reflected over the line y=x . triangle abc has points a (10,2) , b (9,5) and c (6,4) . what is the c' coordinate
Ghella [55]
The coordinates of C are 4,6 because thats the rule for y=x
7 0
3 years ago
Read 2 more answers
Maggie drew triangle and then triangle . Triangle is congruent to triangle only if ∠ is equal to what value?
Phantasy [73]

Answer:

Angle ABE = 58

Step-by-step explanation:

This would fulfill the AAA theorem, or 3 angles needing to be congruent. We got 58 by subtracting 89 and 62 from 180, then multiplying that answer by 2 (because it occupies both triangles).

7 0
3 years ago
It takes one week for a crew of workers to pave 3/5 kilometer of a road. At that rate, how long will it take to pave 1 kilometer
Flauer [41]

Answer:

1.67 weeks

Step-by-step explanation:

Let X= time it will take to pave 1 kilometer?

1 week=3/5 kilometer

X week =1 kilometer

Cross multiply

3/5 X= 1

3X= 5

X= 5/3

1.67 weeks

8 0
3 years ago
PLEASE ANSWER!!!!WILL MARK BRAINLIEST!!!
Setler79 [48]
Hope this is helpful

5 0
3 years ago
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