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2 years ago

5

What is angle BCD A. 80° B. 90° C. 100° D. 110°

1 answer:

alexgriva [62]2 years ago

7 0

Answer:

A

Step-by-step explanation:

it is like your hands hold your hand put to make a l shape that is 90⁰ and imaine that more opened out.

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A water sprinkler sends water out in a circular pattern. How large is the watered

Grace [21]

28.26 feet squared

Work:
A = π r²
A = 3.14 (3²)
A = 3.14 (9)
A = 28.26

6 0

3 years ago

Which quadratic equation is equivalent to (x + 2)^2 + 5(x + 2) - 6 = 0?

Ber [7]

Answer:

$x^2$ + 9x + 8 = 0

Step-by-step explanation:

First, we have to simplify this quadratic equation:

(x+2)^2 + 5(x+2) - 6 = 0

x^2 + 4x + 4 + 5x + 10 - 6 = 0

x^2 + 9x + 8 = 0

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2 years ago

What is 8x+2y-10 over 2

sertanlavr [38]

Answer:

2

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

I need help with this pattern. Can u please tell me how u solved the pattern

andreyandreev [35.5K]

For the first one, repeat it: triangle, checkered square, hexagon

second one, every other triangle should be upside down: triangle down, triangle up, triangle down.

hope this helped!

6 0

3 years ago

A 24.6 g marble sliding to the right at 62.0 cm/s overtakes and collides elastically with a 12.3 g marble moving in the same dir

Softa [21]

Answer:

Velocity of the 24.6 g marble is 31 cm/s.

Step-by-step explanation:

Given:

Marble 1:

Mass of the marble $(m_1)$ = 12.3 gm

Velocity of $m_1$ before collision $v_1_i$ = 15.5 cm/s

Velocity of $m_1$ after collision $v_1_f$ = 77.5 cm/s

Marble 2:

Mass of the marble $(m_2)$ = 24.6 gm

Velocity of $m_2$ before collision $v_2_i$ = 62 cm/s

Velocity of $m_2$ after collision $v_2_f$ = ?

From the law of conservation of momentum, we know that momentum before equals the momentum after :

So,

⇒ $P(i)=P(f)$

⇒ $(m_1\times v_1_i )+(m_2\times v_2_i) =(m_1\times v_1_f)+(m_2\times v_2_f)$

⇒ Plugging the values.

⇒ $(12.3\times 15.5) +(24.6\times 62)=(12.3\times 77.5)+(24.6\times v_2_f)$

⇒ $190.65+1525.2=953.25+24.6\times v_2_f$

⇒ $1715.85=953.25+24.6\times v_2_f$

⇒ $1715.85-953.25=24.6\times v_2_f$ ...subtracting both sides 953.25

⇒ $762.6=24.6\times v_2_f$

⇒ $\frac{762.6}{24.6}\ =v_2_f$ ...dividing both sides with 24.6

⇒ $31=v_2_f$

⇒ $v_2_f =31$ cm/s

The velocity of the 24.6 g marble after the collision is 31 cm/s and it will move opposite to of the 12.3 g marbles that is towards left.

6 0

3 years ago