Answer:
the answer is C. 3. measure the mass of the liquid in both beakers
Answer:
Option c.
Explanation:
Convection - transfer of heat mode is that technique of transfer of heat in which heat and thermal energy can be transferred from one point to another point in the system by the random movement of the molecules of the fluid. This method of transfer of heat or the mechanism of transfer of heat by convection is the most dominant form of transfer of heat in gases and liquids.
Therefore, we can say that convection involves the transfer of heat as a result of the macroscopic and some random movement of the fluid molecules.
I can't answer this question if the structural formula is not given. However, I found a similar problem in terms of wording. Taking this problem to be solved, let's take a look at the structural formula as shown in the second picture. First, you must know the parent chain, which is the longest chain. This is a trial-and-error process. The longest chain which has a branching group that is nearest to the head is the correct numbering. In this case, the longest chain has 8 carbon atoms. Thus, the base of the name if octane. Because a 3-carbon chain is branching from the 4th carbon, the IUPAC name of the compound shown is:
<em>4-propyloctane.</em>
Types of Bonds can be predicted by calculating the difference in electronegativity.
If, Electronegativity difference is,
Less than 0.4 then it is Non Polar Covalent
Between 0.4 and 1.7 then it is Polar Covalent
Greater than 1.7 then it is Ionic
For C and N,
E.N of Nitrogen = 3.04
E.N of Carbon = 2.55
________
E.N Difference 0.49 (Weakly Polar Covalent)
For N and S,
E.N of Nitrogen = 3.04
E.N of Sulfur = 2.58
________
E.N Difference 0.46 (Weakly Polar Covalent)
For K and F,
E.N of Fluorine = 3.98
E.N of Potassium = 0.28
________
E.N Difference 3.70 (Ionic)
For N and N,
E.N of Nitrogen = 3.04
E.N of Nitrogen = 3.04
________
E.N Difference 0 (Non Polar Covalent)
1 is the answer. Both are made up of different particles. Same Letters of the periodic just not built the same ? (CO & CO2)& they are both odorless & colorless
