Answer:
Explanation:
We collected the gas over water; to obtain the true pressure of the gas, we have to correct for the vapor pressure of water. We look up the vapor pressure of water at 24 ºC: 24 torr. The pressure of the evolved gas is, therefore, 738 −24 = 714 torr. 2. We want the molar mass of the
Answer:
9.85
Explanation:
M1V1 =M2V2
6.20×v1= 0.470×0.130
v1 = ( 0.470 × 0.130 ) ÷ 6.20
v1 = 0.0098 L × 1000
V1 = 9.8 ml
Answer: Option (B) is the correct answer.
Explanation:
Both oxygen and fluorine are period 2 elements and when we move across a period then there occurs a decrease in atomic size of the atoms. Hence, the atomic radius of a neutral fluorine atom is smaller than a neutral oxygen atom.
Moreover, atomic number of fluorine is 9 and it has higher nuclear charge due to which it will cause more attraction of electrons. As a result, size of a fluorine ion will be smaller.
On the other hand, size of oxygen atom is larger and has small nuclear charge due to which attraction of electrons by its nucleus will not be strong enough. Hence, the size of
will be larger.
Thus, we can conclude that the statement
has a larger nuclear charge than
has, is correct for the fact that the
ion is smaller than the
ion.
Answer: The last electron will be filled in first orbital of 3p sub-shell.
Explanation: Filling of electrons in orbitals is done by using Hund's Rule.
Hund's rule states that the electron will be singly occupied in the orbital of the sub-shell before any orbital is doubly occupied.
For filling up of the electrons in Sulfur atom having 16 electrons. First 10 electrons will completely fill according to Aufbau's Rule in 1s, 2s and 2p sub-shells and last 6 electrons are the valence electrons which will be filled in the order of 3s and then 3p.
3s sub-shell will be fully filled and the orbitals of 3p sub-shell will be first singly occupied and then pairing will take place. Hence, the last electron will be filled in the first orbital of 3p-sub-shell.
Answer: 14.62 ml
Explanation:
Molarity is defined as the number of moles of solute dissolved per liter of the solution.

where,
n= moles of solute
= volume of solution in ml = 250 ml

Now put all the given values in the formula of molarity, we get


To calculate the volume of base, we use the equation given by neutralization reaction:

where,
are the n-factor, molarity and volume of acid which is 
are the n-factor, molarity and volume of base which is NaOH.
We are given:

Putting values in above equation, we get:

Thus the volume of NaOH solution the student will need to add to reach the final equivalence point is 14.62 ml