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dedylja [7]
3 years ago
14

A viscous liquid is sheared between two parallel disks of radius �, one of which rotates with angular speed Ω, while the other i

s fixed. The velocity field is purely tangential, and the velocity varies linearly with z from: �; = 0 at � = 0 (the fixed disk) to the velocity of the rotating disk at its surface (� = ℎ). Derive an expression for the velocity field between the disks.
Physics
1 answer:
Alexus [3.1K]3 years ago
5 0

Answer:

Upper disk rotates at a constant angular velocity. The velocity at any height from stationery disk, say at x metres

U_o=v(\frac {x}{h}) where v is tangential velocity at radius r from the centre of disk

U_o=r\omega (\frac {x}{h})

The radial component of velocity is given as

U_r=0

The z component of velocity is also given as  

W=0

Total velocity, v= r\omega (\frac {x}{h})\hat e_{o}

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1.53seconds

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time(s)=?

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Making t the subject of the formula :

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A 1022kg Caprice car stopped at an intersection is rear-ended by a 1620kg ranger truck moving with a speed of 14.5m/s. If the ca
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Answer:

Explanation:

mass of car, m = 1022 kg

mass of truck, M = 1620 kg

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initial velocity of car, u = 0 m/s

Let the final velocity of car is v and the final velocity of truck is V.

Collision is elastic, so the coefficient of restitution, e = 1

Use conservation of momentum

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Put in equation (1)

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