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belka [17]
3 years ago
5

When would a life scientist study a nonliving thing such as a rock or lake

Chemistry
1 answer:
VladimirAG [237]3 years ago
3 0
He would study it so he could see how it interacted with the living things around it.

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The following conditions exist in a bacterium and its environment. Environment: 5M NaCl; 1M glucose Inside cell: 3M NaCl; 10M gl
NARA [144]

Answer:

False

Explanation:

Diffusion uses the concentration gradient that has been set up, this is a naturally occurring phenomena, and using a diffusion gradient some small particles can cross over the cell membrane. Some bigger or polar molecules require facilitated diffusion to move these molecules across the membrane.

Facilitated diffusion still uses the gradient for passive transport. This means that ATP is not used to transport molecules.

The reason that glucose will not move into the cell via passive transport is because there is a higher concentration of glucose inside the cell, meaning it needs active transport to move glucose (against the concentration gradient) into the cell.

3 0
3 years ago
A mixture of gases with a pressure of 800.0 mm hg contains 60% nitrogen and 40% oxygen by volume. what is the partial pressure o
klasskru [66]
Hello!

<span>We have the following statement data:
</span>
Data:
P_{Total} = 800 mmHg
P\% N_{2} = 60\%
P\% O_{2} = 40\%
P_{partial} = ? (mmHg)

<span>As the percentage is the mole fraction multiplied by 100:

</span>P =  X_{ O_{2} }*100

<span>The mole fraction will be the percentage divided by 100, thus:
</span><span>What is the partial pressure of oxygen in this mixture? 
</span>
X_{ O_{2} }  =  \frac{P}{100}
X_{ O_{2}} =  \frac{40}{100}
\boxed{X_{ O_{2}} = 0.4}


<span>To calculate the partial pressure of the oxygen gas, it is enough to use the formula that involves the pressures (total and partial) and the fraction in quantity of matter:
</span>
In relation to O_{2} :

\frac{P O_{2} }{P_{total}} = X_O_{2}
\frac{P O_{2} }{800} = 0.4
P_O_{2} = 0.4*800
\boxed{\boxed{P_O_{2} = 320\:mmHg}}\end{array}}\qquad\quad\checkmark
<span>
Answer:
</span><span>b. 320.0 mm hg </span>
7 0
3 years ago
What is the identity of the element which had the following electron configuration? 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^5 ​
kati45 [8]

Answer:

The element with electron configuration 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^5 ​ is manganese (25Mn).

Explanation:

Step 1: Data given

The element with electron configuration 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^5 ​

has 25 electrons.

This element has 2 electrons on the first shell, 8 electrons on the second shell, 13 electrons on the third shell and 2 electrons on the outer shell (valence electrons).

This means this element is part of group VII.

The element with 25 electrons, we can find on the periodic table, with atomic number 25.

The element with electron configuration 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^5 ​ is manganese (25Mn).

5 0
3 years ago
Why did Thomson’s results from experimenting with cathode rays cause a big change in scientific thought about atoms?
IceJOKER [234]

Answer:

D, because he discovered electrons

Explanation:

8 0
3 years ago
Read 2 more answers
The total volume of seawater is 1.5 x 1021L .Assume that seawater contains 3.1 percent sodium chloride by mass and that its dens
son4ous [18]

Answer:

Mass in kg = 4.7*10^19 kg

Mass in tons = 5.2*10^16 tons

Explanation:

<u>Given:</u>

Total volume of sea water = 1.5*10^21 L

Mass % NaCl in seawater = 3.1%

Density of seawater = 1.03 g/ml

<u>To determine:</u>

Total mass of NaCl in kg and in tons

<u>Calculation:</u>

Unit conversion:

1 L = 1000 ml

The volume of seawater in ml is:

=\frac{1.5*10^{21}L*1000ml }{1L} =1.5*10^{24} ml

Mass\ seawater = Density*volume = 1.03g/ml*1.5*10^{24} ml=1.5*10^{24}g

Mass\ NaCl\ in\ seawater = \frac{3.1}{100}*1.5*10^{24}  g=4.7*10^{22} g

To convert mass from g to Kg:

1000 g = 1 kg

Mass\ seawater(kg) = \frac{4.7*10^{22}g*1kg }{1000g} =4.7*10^{19} kg

To convert mass from g to tons:

1 ton = 9.072*10^6 g

Mass\ seawater(tons) = \frac{4.7*10^{22}g*1ton }{9.072*10^{6}g } =5.2*10^{16} tons

5 0
3 years ago
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