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4vir4ik [10]
3 years ago
14

How many mass would be contained in 0.01mol of NaOH

Chemistry
1 answer:
Tpy6a [65]3 years ago
4 0

Answer:

Explanation:

1mol NaOH---->40

0.01mol NaOH------>x

X=40×0.01=0.4

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If I have 72 liters of argon gas held at a pressure of 3.4 atm and a temperature of 225k how many grams of argon do I have
andrezito [222]

Answer:

516.77 grams of Argon gas is present

Explanation:

Using the gas formula

PV = nRT

number of moles (n) = mass / molar weight or mass

P = pressure = 3.4 atm

V = volume = 72 L

R = gas constant = 0.082 L atm mol^-1 K^-1

T = temperature = 225 K

MM = molar mass of Ar = 38.984 g/mol

PV = mRT/ MM

m = PV MM / RT

m = 3.4 * 72 * 38.948 / 0.082 * 225

m =  9534.4704 / 18.45

m = 516.77 grams

the mass of Ar gas you have is 516.77 grams.

5 0
3 years ago
Lavoviser is commonly know as the( brainly dont eveer help)
finlep [7]
Lavoisier is known as the “Father of Modern Chemistry” or the “Father of Chemistry”.

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6 0
3 years ago
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A mixture of carbon dioxide and helium gases is maintained in a 7.91 L flask at a pressure of 1.42 atm and a temperature of 33 °
Crank

Answer:

The gas mixture contains 1.038 grams of helium

Explanation:

<u>Step 1:</u> Data given

Volume of the flask = 7.91 L

Total Pressure = 1.42 atm

Temperature = 33 °C

Mass of CO2 = 8.25 grams

Molar mass of CO2 = 44.01 g/mol

Molar mass of He = 4 g/mol

<u>Step 2</u>: Calculate total number moles of gas

p*V = n*R*T

⇒ p = the pressure = 1.42 atm

⇒ V = the volume = 7.91 L

⇒ n= the number of moles = TO BE DETERMINED

⇒ R = the gas constant = 0.08206 L* atm/K*mol

⇒ T = the temperature = 33 °C = 306 Kelvin

n = (p*V)/(R*T)

n = (1.42*7.91)/(0.08206 * 306)

n = 0.447 moles

<u>Step 3</u>: Calculate moles of CO2

Moles CO2 = mass CO2 / Molar mass CO2

Moles CO2 = 8.25 grams / 44.01 g/mol

Moles CO2 = 0.1875 moles

<u>Step 4:</u> Calculate moles of Helium

Moles Helium = total moles of gas - moles of CO2

Moles Helium = 0.447 - 0.1875 = 0.2595 moles of helium

<u>Step 5: </u> Calculate mass of helium

Mass of helium = moles of helium * molar mass of helium

Mass of helium = 0.2595 moles * 4 g/mol

Mass of helium = 1.038 grams

The gas mixture contains 1.038 grams of helium

8 0
3 years ago
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3 years ago
Carbon-14 is an isotope used in carbon dating. The nucleus becomes Nitrogen-14 through beta decay. Its half-life is 5370 years.
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If the half-life of 14C is 5730 years, when this period of time has passed it will have been halved, it is called the exponential decay law of radioactive isotopes.

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