1. In 1687 following 18 months of intense and effectively nonstop work
2.Hooke
3.Halley
4. Halley urged newton to write Principia mathematica and when the Royal society declined to pay the cost of publishing Halley paid for it out of his own pocket
5.Through using a telescope Galileo Galilei was able to prove the theories of sciences Isaac newton
6. He believe that the speed of an object motion is proportional to the force being applied and inversely proportional to the density of the medium he reason that the object moving in a void would move in definitely fast and thus any and all objects
7. An object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force
8.gottfried wilhelm von leibniz
Answer:
Final temperature = T₂ = 155.43 °C
Explanation:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Given data:
Mass of coin = 4.50 g
Heat absorbed = 54 cal
Initial temperature = 25 °C
Specific heat of copper = 0.092 cal/g °C
Final temperature = ?
Solution:
Q = m.c. ΔT
ΔT = T₂ -T₁
Q = m.c. T₂ -T₁
54 cal = 4.50 g × 0.092 cal/g °C × T₂ -25 °C
54 cal = 0.414 cal/ °C × T₂ -25 °C
54 cal /0.414 cal/ °C = T₂ -25 °C
130.43 °C = T₂ -25 °C
130.43 °C + 25 °C = T₂
155.43 °C = T₂
Answer:
Dissolve 226 g of KCl in enough water to make 1.5 L of solution
Explanation:
1. Calculate the moles of KCl needed
![n = \text{1.5 L} \times \dfrac{\text{2 mol}}{\text{1 L}}= \text{3.0 mol}](https://tex.z-dn.net/?f=n%20%3D%20%5Ctext%7B1.5%20L%7D%20%5Ctimes%20%5Cdfrac%7B%5Ctext%7B2%20mol%7D%7D%7B%5Ctext%7B1%20L%7D%7D%3D%20%5Ctext%7B3.0%20mol%7D)
2. Calculate the mass of KCl
![m = \text{3.0 mol} \times \dfrac{\text{74.55 g}}{\text{1 mol}}= \text{224 g}](https://tex.z-dn.net/?f=m%20%3D%20%5Ctext%7B3.0%20mol%7D%20%5Ctimes%20%5Cdfrac%7B%5Ctext%7B74.55%20g%7D%7D%7B%5Ctext%7B1%20mol%7D%7D%3D%20%5Ctext%7B224%20g%7D)
3. Prepare the solution
- Measure out 224 g of KCl.
- Dissolve the KCl in a few hundred millilitres of distilled water.
- Add enough water to make 1.5 L of solution.
Mix thoroughly to get a uniform solution.