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alexira [117]
3 years ago
10

which statement is true about the reaction shown by this chemical equation HCl + NaOH ------> NaCl + H2O

Chemistry
2 answers:
bixtya [17]3 years ago
7 0

Answer: It is endothermic

Explanation:

NNADVOKAT [17]3 years ago
3 0

Answer:

A. It is exothermic

Explanation:

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How many moles of chlorine gas are in 1.2m^3 at room temperature and pressure?
marshall27 [118]

Answer:

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Explanation:

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5 0
3 years ago
What is the molarity of a solution containing 60. grams of NaOH dissolved in 400. mL of water?
Hunter-Best [27]

Answer: 3.75 M

Explanation:

400 mL = 0.4 L

NaOH has a molar mass of around 40 g/mol.

\frac{60 grams}{40 g/mol} = 1.5 moles

Molarity = \frac{1.5 moles}{0.4 Liters} = 3.75 M

8 0
3 years ago
How many moles of 0.225 M CaOH2 are present in 0.350 L of solution?
weeeeeb [17]

Answer : The number of moles of solute Ca(OH)_2 is, 0.0788 moles.

Explanation : Given,

Molarity = 0.225 M

Volume of solution = 0.350 L

Formula used:

\text{Molarity}=\frac{\text{Moles of }Ca(OH)_2}{\text{Volume of solution (in L)}}

Now put all the given values in this formula, we get:

0.225M=\frac{\text{Moles of }Ca(OH)_2}{0.350L}

\text{Moles of }Ca(OH)_2=0.0788mol

Therefore, the number of moles of solute Ca(OH)_2 is, 0.0788 moles.

7 0
3 years ago
What is the volume of a gas at 756.14 Torr. If the volume was 588.56 mL at 588.56 torr.
creativ13 [48]

Answer:

Explanation:

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5 0
3 years ago
Read 2 more answers
What volume (in milliliters) of oxygen gas is required to react with 4.03 g of Mg at STP?
BigorU [14]
Mg reaction with O₂ gas will produce MgO so the equation will be
2Mg+O₂⇒2MgO. (You have to find the equation in order two figure out the number of moles of O₂ that will react with 1 mole of MgO).

The first step is to find the number of moles of Mg in 4.03g of Mg.  You can do this by dividing 4.03g Mg by its molar mass (which is 24.3g/mol) to get 0.1658mol Mg.  Then you have to find the number of moles of O₂ that will react with 0.1658mol Mg.  To do this you need to use the fact that 1mol O₂ will react with 2mol Mg (this reatio is from the chemical equation) so you have to multiply 0.1658mol Mg by (1mol O₂)/(2mol Mg) to get 0.0829mol O₂.  From here you would usually use PV=nRT and solve for V However, the question tells us that we are at STP, that means you can use the fact that 22.4L of gas is 1 mol of gas at STP.  Using that information we can find the volume of O₂ gas by mulitlying 0.0829mol O₂ by 22.4L/mol to get 1.857L which equals 1857mL.
therefore, 1857mL of O₂ gas will react with 4.03g of Mg.

I hope this helps. Let me know in the comments if anything is unclear.
6 0
3 years ago
Read 2 more answers
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