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4 years ago

Convert 525 pounds to kilograms using dimensional analysis setup

Physics

1 answer:

kobusy [5.1K]4 years ago

6 0

You can do it I believe in you

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A solid sphere rolls along a horizontal, smooth surface at a constant linear speed without slipping. What is the ratio between t

dsp73

Answer:

option E

Explanation:

given,

Rotational Kinetic Energy, KE_r = $\dfrac{1}{2}I\omega^2$

Moment of inertia of the solid,

$I = \dfrac{2}{5}MR^2$

$\omega = \dfrac{V}{R}$

now,

$KE_r = \dfrac{1}{2}I\omega^2$

$KE_r = \dfrac{1}{2}\times \dfrac{2}{5}MR^2 (\dfrac{V}{R})^2$

$KE_r =\dfrac{1}{5}MV^2$ ......(1)

transnational kinetic energy

$KE_t =\dfrac{1}{2}MV^2$

Total kinetic energy

$KE = \dfrac{1}{2}MV^2 + \dfrac{1}{5} MV^2$

$KE = \dfrac{7}{10}MV^2$

ratio of rotational kinetic energy to the total kinetic energy

$\dfrac{KE_r}{KE_t}=\dfrac{\dfrac{1}{5}MV^2}{\dfrac{7}{10}MV^2}$

$\dfrac{KE_r}{KE_t}=\dfrac{2}{7}$

hence, the correct answer is option E

4 0

3 years ago

820 mol of hydrogen gas hydrogen gas has a volume of 2.00 l at a certain temperature and pressure. what is the volume of 0.125 m

Tcecarenko [31]

To solve this problem, let us first assume that the hydrogen gas acts like an ideal gas. So that we can make use of the ideal gas equation:

P V = n R T

where P is the pressure, V is the volume, n is the number of moles, R is the universal gas constant and T is the absolute temperature

Since it is given that T and P is constant therefore we can write the equation as:

V / n = k

So equating the two conditions:

V1 / n1 = V2 / n2

We can now solve for the new V2 given n2 = 0.125:

2 L / 820 mol = V2 / 0.125 mol

V2 = 3.05 x 10^-4 L

<span>The new volume is about 3.05 x 10^-4 L which is equivalent to 0.3 mL</span>

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4 years ago

The force of gravity is less between two objects that

Aloiza [94]

The force of gravity is less between to objects when the product
of their masses is smaller, or when they are farther apart.

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3 years ago

When a 4-μf capacitor has a potential drop of 20 v across its plates, how much electric potential energy is stored in this capac

Genrish500 [490]

Thew energy stored in a capacitor of capacitance $C$ and voltage between the plates $V$ is

$E=\frac{1}{2} CV^2$ .

Substituting numerical value

$E=\frac{1}{2}(4*10^{-6}) (20)^2\\ E=800\; \mu J$

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4 years ago

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