The 5x5 square grid has 6 , 2 x 2 subgrids and the least value of n for which you can be certain that it will have a 2 x 2 subgrid of grey squares is 12.
<h3>What is a Square ?</h3>
A square is a polygon with four sides and all the sides are equal and parallel and all the angle value is 90 degree.
(a) The 5x5 square grid has 6 , 2 x 2 subgrids.
(b) the least value of n for which you can be certain that it will have a 2 x 2 subgrid of grey squares is 12
as it can be understood from the figure 2 that only the last square doesn't have a pair and the rest all does
more than that will be extra but 12 will be enough to make all the grey squares of 2 x 2 subgrid .
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Answer:
53 I believe
Step-by-step explanation:
add all then divide by how much numbers are there
Hello Friend,here is the solution for your question
<span>so the given function is </span>
y= √(-2cos²x+3cosx-1)
i.e = √[-2(cos²x-3/2+1/2)]
i.e = √[-2(cosx-3/4)²-9/16+1/2]
i.e. = √[-2(cos-3/4)²-1/16]
i.e. = √[1/8-3(cosx=3/4)²]-----------(1)
Now here in this equation is this quantity :-
<span>(cosx=3/4)²----------------(2) is to it's minimum value then the whole equation </span>
<span>i.e. = √[1/8-3(cosx=3/4)²] will be maximum and vice versa </span>
And we know that cosx-3/4 will be minimum if cosx=3/4
<span>therefore put this in (1) we get </span>
(cosx=3/4)²=0 [ cosx=3/4]
<span>hence the minimum value of the quantity (cosx=3/4)² is 0 </span>
<span>put this in equation (1) </span>
we get ,
i.e. = √[1/8-3(cosx=3/4)²]
=√[1/8-3(0)] [ because minimum value of of the quantity (cosx=3/4)² is 0 ]
=√1/8
=1/(2√2)
<span>this is the maximum value now to find the minimum value </span>
<span>since this is function of root so the value of y will always be ≥0 </span>
<span>hence the minimum value of the function y is 0 </span>
<span>Therefore, the range of function </span>y is [0,1/(2√2)]
__Well,I have explained explained each and every step,do tell me if you don't understand any step._
Answer:
Step-by-step explanation:
First we need to write in correct form :
We know how to divide fractions. If we can divide numerator by numerator, denominator by denominator, we just do it. In this example we can not do that.
So, we rewrite first fraction and multiply by reciprocal second ( numerator and denominator change place)
Now, multiply numerator by numerator, denominator by denominator :
Download photomath and it will give u step by step instructions
