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Ksivusya [100]
2 years ago
6

When an excited electron spontaneously emits a photon, which energy transformation takes place

Chemistry
2 answers:
kompoz [17]2 years ago
7 0

When an excited electron spontaneously emits a photon, the energy transformation from potential to kinetic energy takes place.

If an atom is in an excited state means full of energy, it goes from higher energy level to lower energy level. The electron releasing energy in the form of a photon, which is emitted in a random direction.

When the electron returns to a low energy state, it releases the potential energy in the form of kinetic energy so we can conclude that the energy transformation from potential to kinetic energy takes place.

Learn more about excited electron here: brainly.com/question/81112

Learn more: brainly.com/question/25976890

notka56 [123]2 years ago
4 0

Given what we know, we can confirm that when an excited electron spontaneously emits a photon, the energy released is electromagnetic energy.

<h3>What is a Photon and what energy does it release when being emitted?</h3>
  • A photon is a particle.
  • This means that it is one of the smallest forms of matter that we can study.
  • Photons form electromagnetic fields.
  • Therefore, when being emitted by an electron, photons release electromagnetic energy.

Therefore, we can confirm that when an excited electron spontaneously emits a photon, the energy released is electromagnetic energy due to the properties of the photon being emitted.

To learn more about photons visit:

brainly.com/question/24309591?referrer=searchResults

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Select correct examples of linear molecules for five electron groups. Select correct examples of linear molecules for five elect
Shalnov [3]

Explanation:

Formula to calculate hybridization is as follows.

                Hybridization = \frac{1}{2}[V+N-C+A]

where,

V = number of valence electrons present in central atom

N = number of monovalent atoms bonded to central atom

C = charge of cation

A = charge of anion

So, hybridization of BeCl_{2} is as follows.

              Hybridization = \frac{1}{2}[V + N - C + A]

                                    = \frac{1}{2}[2 + 2]

                                    = 2

Hybridization of BeCl_{2} is sp. Therefore, BeCl_{2} is a linear molecule. There will be only two electron groups through which Be is attached.

Similarly, hybridization of XeF_{2} is calculated as follows.

         Hybridization = \frac{1}{2}[V + N - C + A]

                                    = \frac{1}{2}[8 + 2]

                                    = 5

Therefore, hybridization of XeF_{2} is sp^{3}d. Therefore, [tex]XeF_{2} is also a linear molecule. Though there are three lone pair of electrons present on a xenon atom and it is further attached with fluorine atoms through two electron pairs. Hence, there are in total five electron groups.

Thus, we can conclude that out of the given options XeF_{2} is the correct examples of linear molecules for five electron groups.

7 0
2 years ago
Be sure to answer all parts. Calculate the pH of the following two buffer solutions: (a) 1.4 M CH3COONa/1.6 M CH3COOH. (b) 0.1 M
aalyn [17]

Answer:

a) pH = 4.68 (more effective)

b) pH =4.44.

Explanation:

The pH of buffer solution is obtained by Henderson Hassalbalch's equation.

The equation is:

pH =pKa +log\frac{[salt]}{[acid]}

a) pKa of acetic acid = 4.74

[salt] = [CH₃COONa] = 1.4 M

[acid] = [CH₃COOH] = 1.6 M

pH = 4.74 + log \frac{1.4}{1.6}= 4.68

This is more effective as there is very less difference in the concentration of salt and acid.

b) pKa of acetic acid = 4.74

[salt] = [CH₃COONa] = 0.1 M

[acid] = [CH₃COOH] = 0.2 M

pH = 4.74 + log \frac{0.1}{0.2}= 4.44

3 0
3 years ago
How much heat is absorbed in the complete reaction of 3.00 grams of SiO2 with excess carbon in the reaction SiO2(g) + 3C(s) → Si
defon

Answer:

31.24 kJ

Explanation:

  • SiO₂(g) + 3C(s) → SiC(s) + 2CO(g)        ΔH° = 624.7 kJ/mol

First we <u>convert 3.00 grams of SiO₂ to moles</u>, using its <em>molar mass</em>:

  • 3.00 g SiO₂ ÷ 60.08 g/mol = 0.05 mol

Now we <u>calculate the heat absorbed</u>, using the <em>given ΔH°</em>:

If the complete reaction of 1 mol of SiO₂ absorbs 624.7 kJ, then with 0.05 mol:

  • 0.05 mol * 624.7 kJ/mol = 31.24 kJ of heat would be absorbed.
6 0
2 years ago
Convert 1.422g/cm^2 to mg/mm^2
Natalija [7]
The answer is 14.22 mg / (mm^2)
6 0
3 years ago
Given the reaction:
STatiana [176]

answer:

as per the formula of given carbohydrate the answer is 15 moles

explanation:

  • 1 mole carbohydrate contains 6 moles water
  • 2.5 moles contain 6 X 2.5 = 15 moles
7 0
3 years ago
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