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2 years ago

Which of the following is an oxidation-reduction reaction?

Chemistry

1 answer:

Alina [70]2 years ago

5 0

Answer:

last choice

Explanation:

oxidation and reduction can be defined in terms of adding or removing oxygen to a compound

oxidation is gaining oxygen

reduction is to loss oxygen

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How many grams of a 26.9% sugar solution contain 49.0 g of sugar?

Ronch [10]

Answer:

182.156g

Explanation:

grams = 49/.269 = 182.156g needed

6 0

2 years ago

Question 3 help me asap please

e-lub [12.9K]

Its chemical formula H2O, indicates that each of its molecules contains one oxygen and two hydrogen atoms, connected by covalent bonds. The hydrogen atoms are attached to the oxygen atom at an angle of 104.45°. "Water" is the name of the liquid state of H2O at standard conditions for temperature and pressure.

5 0

2 years ago

What is the Ground state electron configuration for lead?

notsponge [240]

Answer:

Lead atoms have 82 electrons and the shell structure is 2.8. 18.32. 18.4.

Explanation:

The ground state electron configuration of ground state gaseous neutral lead is [Xe].

3 0

3 years ago

Can someone SCIENTIFICALLY explain to me the formation of all types of Acid Rain?<br> Plz

faust18 [17]

so basically

some fuels have an impurity in them which is sulfur.

When the fuel undergoes combustion, the sulfur reacts with oxygen in the air to form sulfur dioxide.

the sulfur dioxide reacts with water vapour in the air to form sulfurous acid, which is a type of acid rain.

Also

the high pressures inside a car engine may cause nitrogen and oxygen in the air to react and form oxides of nitrogen. the most common compounds formed inside car engines are NO (nitrogen oxide) and NO2 (nitrogen dioxide)

8 0

2 years ago

A sample of methane gas has a volume of 10 l at a pressure of 1.5 atm and a temperature of 20 °c. what volume does the gas occup

a_sh-v [17]

We can use combined gas laws to solve for the volume of the gas
$\frac{PV}{T}$
where P - pressure, V - volume , T - temperature and k - constant
$\frac{P1V1}{T1} = \frac{P2V2}{T2}$
parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation
T1 - temperature in Kelvin - 20 °C + 273 = 293 K
T2 - 40 °C + 273 = 313 K
substituting the values
$\frac{1.5 atm*10L}{293 K} = \frac{0.9 atm*V}{313K}$
V = 17.8 L
volume of the gas is 17.8 L

7 0

2 years ago