Answer:
Rule: replace x by x - a where a is the number of units that you want to move right. a must be greater than 0. x - - a would move left.
Step-by-step explanation:
You want f(x) to move 3 units to the right.
That would mean that x would be replaced by x - 3. Just to be sure let's try it.
- Suppose you have f(x) = x^2 + 6x + 5 It is graphed as the red line
- Now suppose you want to move 3 units right.
- It would replaced like f(x - 3) = (x - 3)^2 + 6(x - 3) + 5 which is the blue line
- Notice nothing else is changed. The blue line looks exactly like the red line except that it is shifted 3 units to the right.
To solve, set an equation:
First Number: x
Second Number: 2x
x+2x=36
3x=36
divide both sides by 3
x=13
First Number: (x) 12
Second Number: (2x) 24
Answers: 12 and 24
Answer:
AGE = 129 degrees
Step-by-step explanation:
The linear function with the same y-intercept with the graphed function is: table A.
<h3>What is a Linear Function?</h3>
The equation that models a linear function is, y = mx + b, where m is the slope and b is the y-intercept.
Slope of the graphed function = rise/run = - 2/1 = -2
Using one of the points on the line (x, y) = (5, 0) and the slope, m = -2, find the y-intercept (b) by substituting the values into y = mx + b:
0 = -2(5) + b
0 = -10 + b
10 = b
b = 10
The slope (m) of the graphed function is -2, and the y-intercept (b) is: 10.
Slope (m) of table A = change in y/change in x = (14 - 8)/(3 - 1) = 3
Substitute a point (x, y) = (1, 8) and slope (m) = 3 into y = mx + b to find the y-intercept (b):
8 = 3(1) + b
8 - 3 = b
5 = b
b = 5
Therefore the table with the same y-intercept as the graphed function is table A.
Learn more about linear function on:
brainly.com/question/4025726
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Complete Question
The complete question is shown on the first uploaded image
Answer:
First Question
Option A is correct
Second Question
Option C is correct
Third Question

Fourth Question
So substituting for D in (ABC) D = I


This proof that ABC is invertible
Step-by-step explanation:
From the question we are told that
A , B and C are invertible which means that
exist
Now
From the question
(ABC) D = I
Where I is an identity matrix
Now when we multiply both sides by
we have


Now when we multiply both sides by
we have


Now when we multiply both sides by
we have



So substituting for D in the above equation


This proof that ABC is invertible