Answer: The charge per day was $33.67 with a mileage cost of $0.19 per mile.
Step-by-step explanation:
Here's the equations that we will use find the total cost of the trip and the mileage cost
Trip 1 --> 241.50 = 4(days) + 450(miles)
Trip 2 --> 139.00 = 3(days) + 200(miles)
You can see that you are missing 2 variables. Let's let the daily fee = x and the charge per mile = y
241.50 = 4x + 450y
139 = 3x+ 200y
To solve for 2 variables, you can use substitution to isolate for one variable and solve for the other
139 = 3x + 200y
139 - 200y = 3x
x = (139 - 200y) / 3 --> this can be substituted into the first original equation for the x to solve for y.
241.50 = 4x + 450y
241.50 = 4(149 - 200y) / 3 + 450y
x3 (241.50 = 596/3 + 550y/3 )x3
700.5 = 596+550y
104.5=550y
y = 0.19 -> mileage charge
plug this into one of the original equations and solve for x
139 = 3x+ 200y
139 = 3x + 200(0.19)
101=3x
x = $33.67
Solution: the charge per day was $33.67 with a mileage cost of $0.19 per mile.
