The pH of 9.643 of 50 ml of 0.1000 M methylamine solution after the following volume of 0.1000 M HNO₃; where added 0
What is pH Value ?
A figure expressing the acidity or alkalinity of a solution on a logarithmic scale on which 7 is neutral, lower values are more acid and higher values more alkaline.
- n(CH₃NH₂) = Cm x V = 0.1 x 0.05 = 0.005mol
- n(HNO₃) = CM x V = 0.1 x 0 = 0 mol
CH₃NH₂ + H₂O = CH₃NH₃⁺ + OH⁻
1mol CH₃NH₂ => 1 mol OH⁻
0.1 M => X = 0.1 M OH⁻
Methylamine, CH₃NH₂, is a weak base that reacts with water according to the above equation.
- For this reaction at equilibrium,
Kb = 4.4 x 10⁻⁴
Cm (OH⁻) = 0.1 x 4.4 x 10⁻⁴= 4.4 x10⁻⁵ M
pOH = -log [OH⁻] = - log (4.4 x 10⁻⁵) = 4.357
Using ;
pH + pOH = 14
we find the pH value:
pH = 14 - pOH = 14 - 4.357 = 9.643
In the similar way, It can be done for 25,3,50,55 and 60
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Answer:
By emitting an electron and an electron antineutrino, one of the neutrons in the carbon-14 atom decays to a proton and the carbon-14 (half-life of 5,700 ± 40 years) decays into the stable (non-radioactive) isotope nitrogen-14.
Half-life: 5,730 ± 40 years
Names: carbon-14, C-14, radiocarbon
Isotope mass: 14.003241 u
1) Atomic number of magnesium (Mg) is 12, it means that it has 12 protons and 12 electrons.
Electron configuration of magnesium atom: ₁₂Mg 1s² 2s² 2p⁶ 3s².
2) Atomic number of aluminium (Al) is 13, it means that it has 13 protons and 13 electrons., but if it lost one electron, it will have 12 electrons and 13 protons and become aluminium cation Al⁺.
Electron configuration of aluminium cation: ₁₃Al⁺ 1s² 2s² 2p⁶ 3s².
3) Atomic number of silicon (Si) is 14, it means that it has 14 protons and 14 electrons., but if it lost two electrons, it will have 12 electrons and 14 protons and become silicon cation Si²⁺.
Electron configuration of silicon cation: ₁₄Si²⁺ 1s² 2s² 2p⁶ 3s².
The question is incomplete. Complete question is read as:
'<span>One cup of fresh orange juice contains 115 mg of ascorbic acid (vitamin C, C6H8O6). Given that one cup = 218.0 mL calculate the molarity of vitamin C in organic juice.'
..........................................................................................................................
Answer:
Given: weight of solute (ascorbic acid) = 115 mg = 0.115 g
Volume of solution = 218.0 mL = 0.218 L
Molecular weight of ascorbic acid = 176.12 g/mol.
Now, Molarity = </span>
=
<span> =
0.002995 mol/dm3Answer: Molarity of solution = </span>
0.002995 mol/dm3<span>
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