Answer:
1) The final displacement of cyclist is 20.8 km.
2) The average velocity of cyclist is 18.35 m/h
Explanation:
The path traced by the cyclist is as shown in the attached figure
from the attached figure we can see
1) Initial distance covered = 8.0 km east therefore OA = 8.0 km
2) When the cyclist turns and travels 3.2 km west thus AB = 3.2 km
3) From B the cyclist turns and travels 16 km east thus BC = 16.0 km
As we can see that the total displacement is OC = OA- AB + BC = 8.0-3.2+16 = 20.8 km
Thus the final displacement is 20.8 km.
Part b)
By definition of average velocity we have
Answer: B=1.92nT
Explanation:This question uses the Biot-Savart law: the law is an equation that describes the magnetic field created by a current-carrying wire, and allows you to calculate its strength at various points.
B=(μ0/4*π)*q*v*r(unit vector)/r²
Also:
B=(μ0/4*π)*q*v*sin(θ)/r²
Where;
μ0 =permeability of free space = 4πx10-7 Hm-1
B = magnetic field in Tesla
V= velocity
r= radius
Therefore:
B=(4πx10-7/4*π)*q*v*sin(θ)/r^2
B=1x10-7*q*v*sin(θ)/r^2
Using:
q=15x10-3C
v=40m/s
tan(θ)=5/2 so θ=68.2°
r²=5²+2² (Pythagoras Theorem)
B can be calculated as:
B=1x10-7*15x10-3*40*sin(68.2)/(5²+2²)
B=1.92nT
F force
I current
L length of wire in magnetic field
B magnetic field strength
θ angle between wire and magnetic field
if θ = 90°
Answer:
176.9N
Explanation:
The following data were given
wire length,L=37cm=0.37m
linear density=18g/m
tube length,=192cm=1.92m,
speed of sound,v=343m/s
Since it is an open-closed tube, the second harmonic frequency is expressed as
The relationship between the tension, linear density and second harmonic frequency is expressed as
Answer:
Explanation:650
colour* wavelength (nm) energy (eV)
red 650 1.91
orange 600 2.06
yellow 580 2.14
green 550 2.25