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3 years ago

15. The Energy possessed by a body by virtueof its position or state is called :

Physics

1 answer:

shepuryov [24]3 years ago

4 0

Answer:

The Energy possessed by a body by virtue of its position or state is called Potential energy.

Mathematically potential energy can be written as,

Potential energy = mgh

Where 'm' represents mass of the body, 'g' represents gravity of the earth and 'h' represents height of body. Potential energy depends on the height, higher the hight from the surface of the earth, maximum will be the potential energy.

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A 2 kg block is pushed against a spring (k = 400 N/m), compressing it 0.3 m. When the block is released, it moves along a fricti

Kitty [74]

Answer:

$2.29 \mathrm{m} \text { the block slide if the } \mathrm{u}_{\mathrm{s}}=0.4$

$4.58 \mathrm{m} \text { the block slide if the } \mathrm{u}_{\mathrm{k}}=0.2$

Explanation:

Given values

Mass (m) = 2kg

K = 400 N/M

Compressing it 0.3 m

The law of conservation of energy:

$\frac{m v^{2}}{2}+\frac{k x^{2}}{2}=\text { constant }$

$\text { Where, } \frac{m v^{2}}{2} \text { is kinetic energy of the block. }$

$\frac{k \Delta l^{2}}{2}$ Energy of the spring deformation.

M mass of the block

x spring deformation

Therefore, if block left the spring (x = 0)

$\frac{m v^{2}}{2}+0=0+\frac{k \Delta l^{2}}{2}$

Where, Δl is initial spring deformation

$\frac{m v^{2}}{2}=\frac{k \Delta l^{2}}{2}$

$\mathrm{v}^{2}=\frac{k \Delta l^{2}}{m}$

$\mathrm{v}=\sqrt{\frac{k}{m} \times \Delta l^{2}}$

$v=\sqrt{\frac{400}{2} \times(0.3)^{2}}$

$\mathrm{v}=\sqrt{200 \times 0.09}$

The law of conservation of energy:

$\frac{m v^{2}}{2}+m g h=\text { constant }$

Where h is height

$\frac{m v^{2}}{2}+0=0+m g h$

$\frac{m v^{2}}{2}=m g h$

Cancel mass "m" each side

$\mathrm{h}=\frac{v^{2}}{2 g}$

Distance along incline equals

$\begin{array}{ll}{\text { For friction us }} & {\left(L=\frac{h}{u_{s}}\right)} \\ {\text { For friction } u_{k}} & {\left(L=\frac{h}{u_{k}}\right)}\end{array}$

$\begin{array}{l}{\mathrm{u}_{\mathrm{s}}=0.4} \\ {\mathrm{U}_{\mathrm{k}}=0.2} \\ {\text { For friction } \mathrm{u}_{\mathrm{s}}}\end{array}$

$\begin{array}{l}{\mathrm{h}=\frac{v^{2}}{2 g u_{s}}} \\ {\mathrm{L}=\frac{4.24^{2}}{2 \times 9.8 \times 0.4}} \\ {\mathrm{L}=\frac{17.9776}{784}}\end{array}$

$\begin{array}{l}{L=2.29 \mathrm{m}} \\ {2.29 \mathrm{m} \text { the block slide if the } \mathrm{u}_{5}=0.4} \\ {\text { For friction } \mathrm{u}_{\mathrm{k}}} \\ {\mathrm{L}=\frac{4.24^{2}}{2 \times 9.8 \times 0.2}}\end{array}$

$\begin{array}{l}{L=\frac{17.9776}{3.92}} \\ {L=4.58 \mathrm{m}} \\ {4.58 \mathrm{m} \text { the block slide if the } \mathrm{u}_{5}=0.4}\end{array}$

8 0

3 years ago

a water balloon is thrown a target at 18 m/s. if the water balloon has a mass of 0.4 kg, what is the momentum?

Arada [10]

The momentum of the water balloon at the given speed is 7.2 kgm/s.

The given parameters:

Speed of the water balloon, v = 18 m/s
Mass of the balloon, m = 0.4 kg

The momentum of the water balloon is calculated as follows;

P = mv

Substitute the given values of mass and velocity as follows;

P = 0.4 x 18

P = 7.2 kg m/s.

Thus, the momentum of the water balloon at the given speed is 7.2 kgm/s.

Learn more about momentum here: brainly.com/question/7538238

8 0

3 years ago

A dog pulls on a leash with a force of 15 23 is a big dog. The leash makes an angle of 36.7 degrees to the horizontal. What are

ch4aika [34]

Answer:

$x = 12.027N$ and $y = 8.964N$

Explanation:

The first sentence of this question is not explanatory enough. However, I'll assume the force to be 15N

$Force = 15N$

$\theta = 36.7$ to the horizontal

Required

Solve for the x and y components

Since the given angle is to the horizontal, the x and y coordinates are calculated using the following illustrations.

$Sin\theta = \frac{y}{Force}$ ---- y component

$Cos\theta = \frac{x}{Force}$ ---- x component

Calculating the y component.

Substitute 15 for Force and 36.7 for $\theta$

$Sin\theta = \frac{y}{Force}$ becomes

$Sin(36.7) = \frac{y}{15}$

Make y the subject

$y = 15 * Sin(36.7)$

$y = 15 * 0.5976$

$y = 8.964N$

Calculating the x component.

Substitute 15 for Force and 36.7 for $\theta$

$Cos\theta = \frac{x}{Force}$ becomes

$Cos(36.7) = \frac{x}{15}$

Make y the subject

$x = 15 * Cos(36.7)$

$x = 15 * 0.8018$

$x = 12.027N$

Hence, the x and y components of the force are: 8.964N and 12.027N respectively.

6 0

3 years ago

Explain the process that causes dew to form on blades of grass.

AysviL [449]

Answer:

Condensation causes dew to form on blades of grass. This is because the water molecules react to the grass when it is heated, and the surroundings became cool. The molecules would bring to calm and turn to liquid.

Explanation:

I just took the test

8 0

3 years ago

Read 2 more answers

High and low tides are the regular pattern of rising and sinking ocean-water levels. They are caused when the sun's gravity and

MrRa [10]

Answer:

D. The moon is closer to Earth than the sun.

Explanation:

Tides are formed as a consequence of the differentiation of gravity due to the moon across to the Earth sphere.

Since gravity variate with the distance:

$F = G\frac{m1\cdot m2}{r^{2}}$ (1)

Where m1 and m2 are the masses of the two objects that are interacting and r is the distance

For example, see the image below, point A is closer to the moon than point b and at the same time the center of mass of the Earth will feel more attracted to the moon than point B. Therefore, that creates a tidal bulge in point A and point B.

The Sun tidal force contributes to the tidal force of the moon over the earth making high tides higher and low tides lower.

However, even when the sun is more massive than the moon, it is farther away from the Earth than the moon. So, it is clear by equation 1 that the moon's gravity has a greater effect on Earth's oceans than the sun's gravity.

8 0

3 years ago

15. The Energy possessed by a body by virtueof its position or state is called :​

15. The Energy possessed by a body by virtueof its position or state is called :