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2 years ago

15. The Energy possessed by a body by virtueof its position or state is called :

Physics

1 answer:

shepuryov [24]2 years ago

4 0

Answer:

The Energy possessed by a body by virtue of its position or state is called Potential energy.

Mathematically potential energy can be written as,

Potential energy = mgh

Where 'm' represents mass of the body, 'g' represents gravity of the earth and 'h' represents height of body. Potential energy depends on the height, higher the hight from the surface of the earth, maximum will be the potential energy.

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The stopping sight distance for a car traveling at 50 mph is 461 ft (including both perception-reaction distance and braking dis

Ivan

Answer:

2.08 s

Explanation:

We are given that

Speed,v=50mph=73.3ft/s

1 mile=5280 feet

1 hour=3600 s

Distance,d=461 ft

t=2.5 s

v'=60 mph=88 ft/s

We have to find the perception reaction time.

Perception reaction distance= $d_p=vt=73.3\ti es 2.5=183.25 feet$

$d_p=d'_p$

$d'_p=v't$

$t'=\frac{183.25}{88}=2.08 s$

4 0

2 years ago

A 30.0 kg child, initially at rest, slides down a 2.0 m tall slide. The child reaches the bottom of the slide with a speed of 6

HACTEHA [7]

Answer:

Explanation:

Total energy is constant

E = mgh + ½mv² + Fd

At the top of the slide, all energy is potential

E = mgh + 0 + 0

At the bottom of the slide, all potential energy has converted to kinetic and work of friction.

mgh = ½mv² + W

W = mgh - ½mv²

W = 30.0[(9.81)(2.0) - ½6²]

W = 48.6 J

5 0

1 year ago

5. a stone propelled from a catapult with a speed of 50 m/s attains a height of 100m. Calculate

omeli [17]

Answer:

<h3>The answer is 2 s</h3>

Explanation:

The time of flight can be found by using the formula

$t = \frac{d}{v} \\$

d is the distance covered

v is the velocity

From the question we have

$t = \frac{100}{50} = \frac{10}{5} \\$

We have the final answer as

Hope this helps you

8 0

2 years ago

An explorer is caught in a whiteout (in which the snowfall is so thick that the ground cannot be distinguished from the sky) whi

alexdok [17]

Actual displacement that he required to move

$d_1 = 5.4 km$ towards North

Displacement that he moved due to snow is

$d_2 = 8.1 km$ at 47 degree North of East

now in vector component form we can say

$d_1 = 5.4 \hat j$

$d_2 = 8.1 cos47 \hat i + 8.1 sin47 \hat j$

$d_2 = 5.52 \hat i + 5.92 \hat j$

now the displacement that is more required to reach the destination is given as

$d = d_1 - d_2$

$d = 5.4\hat j - (5.52 \hat i + 5.92\hat j)$

$d = -5.52 \hat i - 0.52 \hat j$

so the magnitude of the displacement is given as

$d = \sqrt{5.52^2 + 0.52^2}$

$d = 5.54 km$

its direction is given as

$\theta = tan^{-1}\frac{0.52}{5.52} = 5.38 degree$

so it is 5.54 km towards 5.38 degree North of West.

4 0

2 years ago

What measurements would you need to calculate the density of a nail?

Elis [28]

It is c, man it is positively c.

4 0

2 years ago

15. The Energy possessed by a body by virtueof its position or state is called :​

15. The Energy possessed by a body by virtueof its position or state is called :