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VLD [36.1K]
3 years ago
13

A stone is thrown vertically upwards. It decelerates at a rate of 9.8m/s. It reaches a greatest

Physics
1 answer:
frez [133]3 years ago
5 0

Answer:

18

Explanation:

brainiest pls

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More questions in the image.
tensa zangetsu [6.8K]

Answer:

2 True

Explanation: The arrows on a motion map should point in the direction of motion.

3 0
3 years ago
Read 2 more answers
A car's position in relation to time is plotted on the graph. What can be said about the car during segment B?
CaHeK987 [17]

we know that

the speed is equal to

speed=\frac{distance}{time}

The slope of the line on the graph is equal to the speed of the car

so

during the segment B the slope of the line is equal to zero

that means

the speed of the car is zero

therefore

<u>the answer is the option B</u>

The car has come to a stop and has zero velocity

5 0
3 years ago
Read 2 more answers
A cylindrical glass that is 10cm high is partially filled with water. You see the glass in two positions. What is the height of
olga2289 [7]

Answer:

5 cm.

Explanation:

If the glass is located upright, the height of water is about 5 cm because the height of glass is 10 cm and it is partially filled with water and we know that partial means 50 percent of something and here 50 percent of glass is 5 cm. If the glass is slightly bend, so we can't find its right height so the proper height of water is attain if it is placed on flat table and present upright.

4 0
3 years ago
Two small frogs simultaneously leap straight up from a lily pad. Frog A leaps with an initial velocity of 0.551 m/s, while frog
goblinko [34]

Answer:

d = .076 m

Explanation:

The time for frog A can be calculated from  equation of motion

v_f = v_o + at

where v_f is final velocity, a is acceleration due to gravity

so from given data we have

-0.551= 0.551 + (-9.8)(t)

t = 0.112 sec

Now we will use that time for frog B

v_f = v_o + at

v_f = 1.23 + (-9.8)(0.112)

v_f = 0.128 m/s(Note its positive)

For the displacement

s = v_o t + 0.5at^2

s = (1.23)(0.112) + (.5)(-9.8)(0.112)^2

d = .076 m

6 0
3 years ago
A proton of mass is released from rest just above the lower plate and reaches the top plate with speed . An electron of mass is
xenn [34]

Answer:

  v = √ 2e (V₂-V₁) / m

Explanation:

For this exercise we can use the conservation of the energy of the electron

At the highest point. Resting on the top plate

         Em₀ = U = -e V₁

At the lowest point. Just before touching the bottom plate

        Emf = K + U = ½ m v² - e V₂

Energy is conserved

         Em₀ = Emf

          -eV₁ = ½ m v² - e V₂

           v = √ 2e (V₂-V₁) / m

Where e is the charge of the electron, V₂-V₁ is the potential difference applied to the capacitor and m is the mass of the electron

3 0
4 years ago
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