A stone is thrown vertically upwards. It decelerates at a rate of 9.8m/s. It reaches a greatest

attashe74 [19]

Answer:

A. There are multiple paths that electrons can take through the circuit, and it is possible for the electron to pass through one circuit component but not another.

Explanation:

Parallel arrangement of components in an electric circuit puts different parts of the circuit on different branches. In a parallel connection, there are multiple paths for the electrons to take, and it is possible for electrons to pass through on circuit component without going through another. This is the reason why If there is a break in one branch of the circuit, electrons can still flow in other branches, and the same reason why one bulb going off in your home does prevent the other components in your home from coming on (your home is wired in a parallel electric circuit).

5 0

3 years ago

Plzzz HELP MEEEE.

galina1969 [7]

Answer:

D. The state of motion of an object with mass

Explanation:

Specifically, momentum is mv, mass times velocity

7 0

3 years ago

A simple pendulum is used to measure gravity using the following theoretical equation,TT=2ππ�LL/gg ,where L is the length of the

Elina [12.6K]

Answer:

g ±Δg = (9.8 ± 0.2) m / s²

Explanation:

For the calculation of the acceleration of gravity they indicate the equation of the simple pendulum to use

T = $2\pi \sqrt{ \frac{L}{g} }$

T² = $4\pi ^2 \frac{L}{g}$ 4pi2 L / g

g = $4\pi ^2 \frac{L}{T^2}$

They indicate the average time of 20 measurements 1,823 s, each with an oscillation

let's calculate the magnitude

g = $4\pi ^2 \frac{0.823}{1.823^2}$ 4 pi2 0.823 / 1.823 2

g = 9.7766 m / s²

now let's look for the uncertainty of gravity, as it was obtained from an equation we can use the following error propagation

for the period

T = t / n

ΔT = $\frac{dT}{dt}$ Δt + $\frac{dT}{dn}$ ΔDn

In general, the number of oscillations is small, so we can assume that there are no errors, in this case the number of oscillations of n = 1, consequently

ΔT = Δt / n

ΔT = Δt

now let's look for the uncertainty of g

Δg = $\frac{dg}{dL}$ ΔL + $\frac{dg}{dT}$ ΔT