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vampirchik [111]
3 years ago
11

A proton has been accelerated from rest through a potential difference of -1350 V. What is the proton's kinetic energy, in elect

ron volts? What is the proton's kinetic energy, in joules? What is the proton's speed?
Physics
1 answer:
Luba_88 [7]3 years ago
8 0

Answer:

1 eV = 1.60 * 10^-19 J      work done in accelerating electron thru 1 V

KE (total energy) = 1350 ^ 1 eV     (note proton goes from +  to -)

KE = 1.60 * 10^-19 * 1350 = 2.16 * 10^-16 Joules

1/2 m v^2 = KE = 2.16 * 10^-16 J

v^2 = 4.32 * 10E-16 / 1.67 * 10-27 = 2.59 * 10^11

v = 5.09 * 10^5 m/s

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