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vampirchik [111]
3 years ago
11

A proton has been accelerated from rest through a potential difference of -1350 V. What is the proton's kinetic energy, in elect

ron volts? What is the proton's kinetic energy, in joules? What is the proton's speed?
Physics
1 answer:
Luba_88 [7]3 years ago
8 0

Answer:

1 eV = 1.60 * 10^-19 J      work done in accelerating electron thru 1 V

KE (total energy) = 1350 ^ 1 eV     (note proton goes from +  to -)

KE = 1.60 * 10^-19 * 1350 = 2.16 * 10^-16 Joules

1/2 m v^2 = KE = 2.16 * 10^-16 J

v^2 = 4.32 * 10E-16 / 1.67 * 10-27 = 2.59 * 10^11

v = 5.09 * 10^5 m/s

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Which of the following statements are true of thermal energy and kinetic energy?
Irina-Kira [14]
This question is asking you to determine if individual atoms or systems, or both have these types of energy. A system would be "all the molecules or atoms" whereas an individual atom is "each of the molecules or atoms."

Answers: 

A. All the molecules or atoms in motion have kinetic energy.

B. Each molecule or atom in motion has kinetic energy.

D. All the molecules or atoms in motion have thermal energy.

The only incorrect answer is C because individual atoms don't have thermal energy, only when they interact with other atoms. Still, atoms do have kinetic energy, which has the potential to turn into heat energy in these interactions.

Hope this helps!
7 0
3 years ago
Which object has the least amount of Kinect energy
Angelina_Jolie [31]

Answer: Could you please add the answer choices.

Explanation:

Thank you :)

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3 years ago
GIVING BRAINLIEST PLEASE HELP ME!!!
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Answer:

I'm Pretty sure the answer your looking for is C

4 0
3 years ago
How much energy ( in joules ) is released when 0.06 kilograms of mercury is condensed to a liquid at the same temperature ?
aleksley [76]

Answer:

B. 17,705.1 J

Explanation:

The hear released when the mercury condenses into a liquid is given by:

Q=m \lambda_v

where

m = 0.06 kg is the mass of the mercury

\lambda_v is the latent heat of vaporization

For mercury, the latent heat of vaporization is \lambda_v = 296 kJ/kg, so the heat released during the process is:

Q=(0.06 kg)(296 kJ/kg)=17.76 kJ = 17,760 J

So, the closest option is

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5 0
3 years ago
Read 2 more answers
A 1000-kg car is driving toward the north along a straight horizontal road at a speed of 20.0 m/s. The driver applies the brakes
Nitella [24]

Answer:

The value of F= - 830 N

Since the force is negative, it implies direction of the force applied was due south.

Explanation:

Given data:

Mass = 1000-kg

Distance, d = 240 m

Initial velocity, v1 = 20.0 m/s

Final velocity, v2 = 0 (since the car came to rest after brake was applied)

v2²= v1² + 2ad (using one of the equation of motion)

0=  20² + (2 x a x  240)

0= 400 + 480 a

a = - 400/480

a = - 0.83 m/s²

Then, imputing the value of a into

F = ma

F = 1000 kg x ( - 0.83 m/s²)

F= - 830 N

The car was driving toward the north, and since the force is negative, it implies direction of the force applied was due south.

3 0
3 years ago
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