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vampirchik [111]
3 years ago
11

A proton has been accelerated from rest through a potential difference of -1350 V. What is the proton's kinetic energy, in elect

ron volts? What is the proton's kinetic energy, in joules? What is the proton's speed?
Physics
1 answer:
Luba_88 [7]3 years ago
8 0

Answer:

1 eV = 1.60 * 10^-19 J      work done in accelerating electron thru 1 V

KE (total energy) = 1350 ^ 1 eV     (note proton goes from +  to -)

KE = 1.60 * 10^-19 * 1350 = 2.16 * 10^-16 Joules

1/2 m v^2 = KE = 2.16 * 10^-16 J

v^2 = 4.32 * 10E-16 / 1.67 * 10-27 = 2.59 * 10^11

v = 5.09 * 10^5 m/s

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A car drives 23m/s east for 35 seconds. What is the displacement?
Lina20 [59]

Answer:

805m

Explanation:

Speed = displacement/time

Speed = 23m/s

Time = 35s

Displacement = speed × time

= 23 × 35

= 805m

5 0
3 years ago
A cube 6.0 cm on each side is made of a metal alloy. After you drill a cylindrical hole 2.0 cm in diameter all the way through a
Crank

To solve this problem it is necessary to apply the concepts related to Newton's second law, the definition of density and the geometric relationships that allow us to find the volume of the figures presented.

For the particular case of the Cube with equal sides its volume is determined by

V_c = l^3

V_c = 6^3 = 216cm^3

In the case of perforated material we have that its volume is given according to the cylindrical geometry, that is to say

V_d = \pi r^2*l

V_d = \pi (\frac{2}{2})^2*6

V_d = 6\pi cm^3

In this way the net volume would be

\Delta V = V_c-V_d

\Delta V = 216cm^3-6\pi cm^3

\Delta V = 197.15cm^3 = 197.15*10^{-6}m^3

We need to find the mass, but we have the Weight and Gravity so from Newton's second Law

F= mg

m = \frac{F}{g}

m = \frac{6.6}{9.8}

m = 0.673kg

PART A) From the relation of density as a unit of mass and volume we have to

\rho = \frac{m}{V}

\rho = \frac{0.673}{197.15*10^{-6}}

\rho = 3413.64kg/m^3

PART B) To find the weight of the cube then we apply the ratio of

W = mg

W = V\rho g

W = (216*10^{-6})(3413.64)(9.8)

W = 7.22N

3 0
3 years ago
A boy drags a suitcase along the ground with a force of 100 N. If the frictional force opposing the motion of the suitcase is 50
stira [4]
Fortunately, 'force' is a vector.  So if you know the strength and direction
of each force, you can easily addum up and find the 'resultant' (net) force.

When we talk in vectors, one newton forward is the negative of
one newton backward.   Hold that thought, while I slog through
the complete solution of the problem.


            (100 N forward) plus (50 N backward)

        =  (100 N forward) minus (50 N forward)

        =           50 N forward .

That's it.
Is there any part of the solution that's not clear ?

4 0
3 years ago
In any given wave, when the frequency of the wave doubles (f = 2f), which of the following other changes would also take place?
Zanzabum

Answer:

The correct answer is -

B. The velocity would double (v = 2v).

C. The wavelength would be half (λ = λ/2).

Explanation:

A wave has a speed or velocity that is related to the wavelength of the wave and the frequency of the wave and this relationship can be represented by the following equation-

Wave velocity V = Wavelength (λ) * Frequency (f)

Frequency (f) = Velocity (V) / Wavelength(λ).

The frequency and wavelength are inversely proportional and frequency and velocity are directly proportional to each other.

So, if f = 2f then,

putting value in the formula,

2f = 2v/λ, which means, f = 2v and f = λ/2

when the frequency is doubled, the wavelength will be halved and velocity will be doubled.

6 0
3 years ago
If a pendulum has a period of 4 seconds at the north pole with gravity force 9.83 ms^-2 and a 3.97m pendulum length, how could t
sladkih [1.3K]

Answer:

The same pendulum could be adjusted to have the same period, in the equator must have a length of 3.949m.

Explanation:

Tnp= 4 sec

gnp= 9.83 m/sec²

Lnp= 3.97m

Tequ= 4 sec

gequ= 9.78 m/sec²

Lequ=?

Lequ= (Lnp* gequ) / gnp

Lequ= 3.949 m

5 0
3 years ago
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