Answer:
The tension in string P is 25 N, while that of Q is 85 N.
Explanation:
Considering the conditions for equilibrium,
i. Total upward force = Total downward force
+ = 110 N
ii. Taking moment about P,
clockwise moment = anticlockwise moment
110 × (2.5 - 0.8) = × (3 - 0.8)
110 × 1.7 = × 2.2
187 = 2.2
=
= 85 N
From the first condition,
+ = 110 N
+ 85 N = 110 N
= 110 - 85
25 N
Therefore, the tension in string P is 25 N while that of Q is 85 N.
Answer:
15 grams
Explanation:
9 sugar cubes + 2 teaspoons of baking soda + 2 grams of the sugar cubes each + 3 grams of baking soda = 15g.
From what i know it is c. it is a lever
Answer:
initial velocity (u) = 200m/s
final velocity (v) = 350 m/s
time (t) = 15s
acceleration (a) = ?
NOW,
a=v-u/t
a= 350-200/15
a= 50/15
a= 3.3333
Explanation:
it's too easy just u need to understand the question . and go according to it's content .
main thing to memorize is it's simple formula.
I HAVE SOLVE THIS QNA. IN VERY
SIMPLE AND UNDERSTANDABLE FORM.
I høpë u hađ uņdērstøöď ťhìs şølutîóñ
:verý ×wəłł.
Explanation:
Given parameters:
Jermaine runs exactly 2 laps around a 400m track
Start time = 3:02:00PM
End time = 3:04:45PM
Unknown:
Distance traveled = ?
Speed = ?
Displacement = ?
Velocity = ?
Solution:
To solve this problem, we need to find the distance and time first;
Distance = 2 x 400 = 800m
Time taken = 3:04:45PM - 3:02:00PM = 165s
Speed = = = 4.85m/s
The velocity of the body is 0m/s and so is the displacement.
This is because the starting and finishing position of the Jermaine is the same.