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Aleks04 [339]
3 years ago
5

CO2 + H2O --> C2H2 + O2

Chemistry
1 answer:
vagabundo [1.1K]3 years ago
5 0

Answer:

C2H2 + 5 O2 = 4 CO2 + 2 H2O

Add / Edited: 27.09.2014 / 25.01.2015

Evaluation of information: 5.0 out of 5 / number of votes: 2

Source: https://chemiday.com/en/reaction/3-1-0-339

Explanation:

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Are the activities exothermic or endothermic?​
Alexandra [31]

Answer:

The first 5 are exothermic reaction because heat is in product means heat is evolved or given out.

And last no reaction shows that heat is required so last reaction is endothermic reaction.

Explanation:

And heat is evolved in exothermic reaction and heat is absorbed in endo thermic reaction

6 0
3 years ago
Which of the following has the lowest Ka?a. carbonic acid b. dihydrogen phosphate c. phosphoric acid d. bicarbonate
Naya [18.7K]

Explanation:

A compound or molecule which will have least dissociation and that is not able to given hydrogen ion easily upon dissociation will also have a low value of K_{a}.

Dissociation of the given compounds or species will be as follows.

 H_{2}CO_{3} \rightleftharpoons H^{+} + HCO^{-}_{3}

 H_{2}PO^{-}_{4} \rightleftharpoons H^{+} + HPO^{-}_{4}

 H_{3}PO_{4} \rightleftharpoons H_{+} + H_{2}PO^{-}_{4}

As, chemical formula of bicarbonate is HCO^{-}_{3} and due to the presence of a negative charge it is difficult to lose a positively charged hydrogen ion. This is because oppositely charged ions will be bonded by strong force of attraction.

Hence, it will not easily lose a hydrogen ion due to which bicarbonate has the lowest K_{a}.

Thus, we can conclude that out of the given species bicarbonate has the lowest K_{a}.    

7 0
3 years ago
Calculate the molarity of 90.0 mL of a solution that is 0.92 % by mass NaCl. Assume the density of the solution is the same as p
jeka94
Answer is: molarity is 0,155 M.
V(solution) = 90,0 mL = 0,09 L.
ω(NaCl) = 0,92% ÷ 100% = 0,0092.
d(solution) = 1 g/mL.
m(solution) = V(solution) · d(solution).
m(solution) = 90 mL · 1 g/mL = 90 g.
m(NaCl) = 90 g · 0,0092 = 0,828 g.
n(NaCl) = 0,828 g ÷ 58,4 g/mol.
n(NaCl) = 0,014 mol.
c(solution) = 0,014 mol ÷ 0,09 L.
c(solution) = 0,155 mol/L.

8 0
3 years ago
37.5g/mL converted to kg/L
PIT_PIT [208]
37.5 g/mL
37.5 0.001kg/0.001L
37.5 kg/L
3 0
3 years ago
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