The total energy of the system remains the same.
Answer:
The number of bright fringes per unit width on the screen is,
Explanation:
If d is the separation between slits, D is the distance between the slit and the screen and is the wavelength of the light. Let x is the number of bright fringes per unit width on the screen is given by :
is the wavelength
n is the order
If n = 1,
So, the the number of bright fringes per unit width on the screen is . Hence, the correct option is (B).
The best answer would be C.
The mass of an element depends on the number of particles found in the nucleus of the atom. Atomic mass can be computed by adding the number of protons and the number of neutrons. Protons and neutrons are found in the nucleus of an atom. So the answer must be letter C.
A delightful problem !
I'm pretty sure that what we need here is the speeds, not the velocities,
and that's the way I'm going to do it.
Regular speed is (distance covered) divided by (time to cover the distance) .
Angular speed is very much the same.
It's
(angle turned) divided by (time to turn the angle) .
<u>Earth's orbit around the sun</u>:
..... Once per year.
..... Roughly 360° in 365 days ..... <em>almost exactly 1° per day</em>.
Let's see what it is more accurately:
(360°) / (<span>365.25636<span> days) = 0.985609° per day.
============================================
<u>Earth's rotation on its axis</u>:
..... Once per "day".
..... Roughly 360° in 24 hours ..... <em>almost exactly 15° per hour</em>.
This one is slightly trickier to do more accurately, because a day is
not necessarily 24 hours. It depends on what you call 1 day.
-- If you say the day is the period of time between when the sun is
highest in the sky, then that averages out to 24 hours in the course
of a year.
-- If you say that the day is the period of time it takes for a star
to reach the same point in the sky tomorrow night, then that's </span></span>
23 hours, 56 minutes, 4.09 seconds .
Using this to calculate the angular speed of rotation, you get
(360°) / (23h 56m 4.09s) = 15.041° per hour
JOULES and NEWTONS I hope that helps sorry for the caps