A liquid of density 830 kg/m3 flows through a horizontal pipe that has a cross-sectional area of 1.20 x 10-2 m2 in region A and
a cross-sectional area of 9.40 x 10-2 m2 in region B. The pressure difference between the two regions is 6.50 x 103 Pa. What are (a) the volume flow rate and (b) the mass flow rate?
1 answer:
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A) 2.64 H
The maximum height that the expelled rock can reach can be found by using the equation:
where
v = 0 is the velocity at the maximum height
u is the initial velocity
g is the acceleration of gravity
d is the maximum height
Solving for d,
We see that the maximum heigth is inversely proportional to g. On the Earth,
and
So we can write:
where H' is the maximum height reached on Mars, and is the acceleration of gravity on Mars. Solving for H',
B) 2.64T
The time after which the rock reaches the maximum height can be found by using
where
v = 0 is the velocity at the maximum height
u is the initial velocity
Solving for t,
The total time of the motion is twice this value, so:
So we see that it is inversely proportional to g.
On the Earth, t = T. So we can write:
where T' is the total time of the motion on Mars. Solving for T',