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Stella [2.4K]
4 years ago
12

A straightforward method of finding the density of an object is to measure its mass and then measure its volume by submerging it

in a graduated cylinder. What is the density (in g/cm3) of a 300 g rock that displaces 89.0 cm3 of water? (Note that the accuracy and practical applications of this technique are more limited than a variety of others that are based on Archimedes' principle.)
Physics
1 answer:
Thepotemich [5.8K]4 years ago
4 0

Answer:

<em>The density of rock = 3.37 g/cm³</em>

Explanation:

Density: Density can be defined as the ratio of the mass of a body to the volume. The S.I unit of density is kg/m³. It can be expressed mathematically as ,

D = M/V............................................... Equation 1

Where D = density of the body, M = mass of the body, V = volume of the body.

From Archimedes' principle, a body will displace a volume of water equal to  its volume.

Therefore, Volume of the object = volume of water displaced

<em>Given: M = 300 g, V = volume of water displace = 89.0 cm³.</em>

<em>Substituting these values into equation 1</em>

<em>D = 300/89</em>

<em>D = 3.37 g/cm³</em>

<em>The density of rock = 3.37 g/cm³</em>

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a nonrelativistic proton is confined to a length of 2.0 pm on the x-axis. what is the kinetic energy of the proton if its speed
Elina [12.6K]

Answer:

K = 1.29eV

Explanation:

In order to calculate the kinetic energy of the proton you first take into account the uncertainty principle, which is given by:

\Delta x \Delta p\geq \frac{h}{4\pi}      (1)

Δx : uncertainty of position = 2.0pm = 2.0*10^-12m

Δp: uncertainty of momentum = ?

h: Planck's constant = 6.626*10^-34 J.s

You calculate the minimum possible value of Δp from the equation (1):

\Delta p=\frac{h}{4\pi \Delta x}=\frac{6.626*10^{-34}J.s}{4\pi(2.0*10^{-12}m)}\\\\\Delta p=2.63*10^{-23}kg.\frac{m}{s}

The minimum kinetic energy is calculated by using the following formula:

k=\frac{(\Delta p)^2}{2m}       (2)

m: mass of the proton = 1.67*10^{-27}kg

k=\frac{(2.63*10^{-23}kgm/s)^2}{2(1.67*10^{-27}kg)}=2.08*10^{-19}J

in eV you have:

2.08*10^{-19}J*\frac{6.242*10^{18}eV}{1J}=1.29eV

The kinetic energy of the proton is 1.29eV

7 0
3 years ago
A string of length 0.67 m and mass 2.0 g is held at both ends under tension. The string
ikadub [295]

Answer:

The value is \lambda = 0.335 \  m  

Explanation:

From the question we are told that

     The length of the string is  l  =  0.67 \  m

      The mass is  m  = 2.0 \  g  =  0.002 \  kg

      The frequency produced at  fourth harmonic vibration(i.e n =4 )  is  f =  700 \  Hz

  Generally the wavelength of the string is  mathematically represented as

            \lambda = \frac{ 2L }{n }

=>          \lambda = \frac{ 2 * 0.67 }{ 4 }  

=>          \lambda = 0.335 \  m  

7 0
3 years ago
In one cycle, a heat engine takes in 1000 J of heat from a high-temperature reservoir, releases 600 J of heat to a lower-tempera
Talja [164]

Answer:

η = 40 %  

Explanation:

Given that

Qa ,Heat addition= 1000  J

Qr,Heat rejection= 600 J

Work done ,W= 400 J

We know that ,efficiency of a engine given as

\eta=\dfrac{W(net)}{Q(heat\ addition)}

Now by putting the values in the above equation ,then we get

\eta=\dfrac{400}{1000}

η = 0.4

The efficiency in percentage is given as

η = 0.4  x 100 %

η = 40 %

Therefore the answer will be 40%.

4 0
4 years ago
Which material will heat up the most quickly if placed near a heat source?
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Answer:

Metal

Explanation:

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7 0
3 years ago
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A uniform stick 1.0 m long with total mass of 270 g is pivoted at it's center.
evablogger [386]

Answer:

ω = 3.66 rad/s

Explanation:

Given that

L= 1 m

M = 270 g = 0.27 kg

m = 3 g

u= 250 m/s

v= 140 m/s

We know that moment of inertia of the rod about it center

I=\dfrac{1}{12}ML^2

I=\dfrac{1}{12}0.27\times 1^2

I=0.0225 kg.m²

The initial angular momentum

L₁ = m u r

Final angular momentum

L₂= I ω+m v r

Here r= L/4

r= 0.25 m

There is no any external torque ,it means that angular momentum will be conserve

L₁  = L₂

m u r =  I ω+m v r

m r (u - v)=I ω

Now by putting the values

m r (u - v)=I ω

0.003 x 0.25 x (250- 140)=0.0225 x ω

ω = 3.66 rad/s

5 0
4 years ago
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