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Natali [406]
2 years ago
6

Find the lowest common denominator (LCD) of these fractions. 3 5 8x 18x

Mathematics
1 answer:
padilas [110]2 years ago
8 0

Answer:

72x

Step-by-step explanation:

8x = 2 * 2 * 2 * x   = 2³ * x

18x = 2 * 3 * 3 * x = 2 * 3² * x

LCD = 2³ * 3² * x = 8 * 9 * x = 72x

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Sales Hester sells televisions. She earns a fixed amount for each television and an additional $20 if the buyer gets an extended
Butoxors [25]

Answer:

$80

Step-by-step explanation:

15(x+20) = 1500

15x + 300 = 1500

Subtract 300 from each side

15x = 1200

Divide each side by 15

x = 80

8 0
2 years ago
How many solutions does the equation x_1 +x_2+x_3+x_4+x_5=21 have where x_1, x_2, x_3, x_4, and x_5 are nonnegative integers and
omeli [17]

Step-by-step explanation:

x_{1} + x_{2} + x_{3} + x_{4} + x_{5} = 21\\     (given)

Let us consider :

x_{1} = t_{1} + 1

x_{2} = t_{2}

x_{3} = t_{3}

x_{4}  = t_{4}

x_{5} = t_{5}

Now, by substituting the above considerations in the above equation, we get:

t_{1} + 1 + t_{2} + t_{3} + t_{4} + t_{5} = 21\\

t_{1}  + t_{2} + t_{3} + t_{4} + t_{5} = 20\\

where,

t_{i} \geq 1

then it follows

n = 20

r = 4

then no. of solutions for the eqn = _{r}^{n + r}\textrm{C}

                                                      = _{4}^{24}\textrm{C}

                                                      = 10626

Answer :

no. of solutions for the eqn 10626

4 0
3 years ago
I just need help solving this problem. Also please don't put the answer into a file because I can't open them. It's also really
dem82 [27]

Answer:

<em>31° </em>

Step-by-step explanation:

5 0
3 years ago
Two sections of a class took the same quiz. Section A had 15 students who had a mean score of 80, and Section B had 20 students
Ksju [112]

Answer:

86

Step-by-step explanation:

In this question, we are asked to calculate the average mean score for a group of students split into two different emerging groups.

We calculate the total score for each of the groups. This is done by multiplying the average score by the number of students.

Total score of section A is 15 * 80 = 1,200

For section B, total score is 20 * 90 = 1,800

Overall score is thus 1200 + 1800 = 3000

We add the scores together and divide by the total number of students in both sections

Average score is thus 3000/35 = 85.71 which is approximately 86

3 0
3 years ago
Pls help due ASAP <br> Show workings pls
kobusy [5.1K]
The answer is c
you (4,4) and another point need to be double (2,-5) so the other point needs to add to (4,-10) so 4 + 0 is 4 and 4 + - 14 = 10
4 0
3 years ago
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