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lesya [120]
3 years ago
14

It is recommended to use a Poisson process to model the number of failures in commercial water

Mathematics
1 answer:
OverLord2011 [107]3 years ago
7 0
A research paper recommends using Poisson process to model the number of failures in commercial water pipes The paper also gives estimates the failure rate in units of failures per 100 miles of pipe per day; for four different types of pipe and for many different years_ For example, for cast iron pipe in 2005, the authors' estimate is the failure rate is 0.0864 failures per 100 miles per day: Suppose a town had 2500 miles of cast iron pipe underground in 2005 What is the probability of at least two failures
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~(~p) is always equivalent to<br><br> 1: q<br> 2: (~(~(~ (~p))))<br> 3: ~P<br> 4: ~q
LUCKY_DIMON [66]
? Wth.....................
7 0
3 years ago
As a salesperson at Roaring Waves Beach Supplies, Carissa receives a monthly base pay plus commission on all that she sells. If
Pani-rosa [81]
Base pay + (rate * sales) = total pay

b + r(400) = 388
b + r(700) = 454

b = 388 - 400r
now sub into 2nd equation
388 - 400r + 700r = 454
-400r + 700r = 454 - 388
300r = 66
r = 66/300
r = 0.22...22% is the rate

substitute for r
b + 400r = 388
b + 400(0.22) = 388
b + 88 = 388
b = 388 - 88
b = 300

so ur equation is : y = 0.22x + 300
y = 0.22(2600) + 300
y = 572 + 300
y = 872......so her salary when selling $2600 worth of stuff is $872
6 0
3 years ago
An airline has 82% of its flights depart on schedule. It has 65% of its flight depart and arrive on schedule. Find the probabili
victus00 [196]

Answer:

0.79

Step-by-step explanation:

Here,  

Let X be the event that the flights depart on time

Let Y be the event that flights arrive on time

So,  

X∩Y will denote the event that the flights departing on time also arrive on time.

Let P be the probability  

P(X∩Y)=0.65

And

P(X)=0.82

We have to find P((Y│X)

We know that

P((Y│X)=P(X∩Y)/P(X) )

=0.65/0.82

=0.79

So the probability that a flight that departs on schedule also arrives on schedule is: 0.79

7 0
3 years ago
This set of ordered pairs is a function (22, 4), (21, 1), (0, 0), (1, 1), and (2, 4).
Mariulka [41]

Answer:

Step-by-step explanation:

You know these ordered pairs are considered a function, because the x intercepts do not repeat themselves. In other words, each input numbers are different. If these ordered pairs were not a function, the x intercept would be repeating. For example,  22 is already a x intercept, (22,4), if 22 was put in as another x intercept like,(22,1) these ordered pairs would not be a function.

3 0
4 years ago
Need help really fast will mark brainliest
Volgvan
I’m pretty sure it’s a
6 0
3 years ago
Read 2 more answers
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