Coulomb interaction is responsible
Answer:
option A is your answer hope it will help you
The hot discharge gas from the refrigerant compressor is normally cooled and condensed at high pressure. This is then passed through an 'Expansion' valve which decreases the pressure to a low level causing expansion of the refrigerant liquid.
<span>The liquid partially vapourises causing a 'Joule's/Thompson' refrigeration effect' which decreases temperature of the refrigerant which then passes to an evaporator coil in the air circulation system of the building. </span>
<span>In the evaporator coil, the heat exchange between the cold refrigerant and the warm air of the building, vaporises and heats the refrigerant which returns to the compressor. </span>
<span>The cycle is repeated until the air temperature reaches the thermostat set-point and switches off the system. </span>
<span>As a Heat pump, the hot refrigerant gas is not evaporating and condensing. </span>
<span>From the compressor discharge, the hot gas is by-passing the cooler/condenser unit and the expansion valve and passes directly to the 'evaporator' coils but now, as the heating medium for the air circulation system where it's cooled by the heat exchange between the hot gas and the cooler air in the building and returns to the compressor in a continuous cycle. </span>
<span>A Thermostat in the system starts and stops the compressor motor according to the heat or cool temperature settings.</span>
Answer is B. both potential and kinetic energy.
Answer:
C. Equals the sum of all forms of energy contained within the system.
D. Equals the heat entering the system at constant volume.
E. Equals the heat entering the system plus the work done on the system
Explanation:
Internal energy is defined as the sum of internal kinetic energy and internal potential energy, that is, the energy contained within the system.
The first law of thermodynamics relates the change in the internal energy with the heat entering the system (Q) and work done on the system (W), with the following expression:
![\Delta U=Q+W](https://tex.z-dn.net/?f=%5CDelta%20U%3DQ%2BW)
If the system is at constant volume the work done is zero. Therefore, the heat entering the system increases its internal energy:
![\Delta U=Q](https://tex.z-dn.net/?f=%5CDelta%20U%3DQ)