Like this variation of the problem! :)
We calculate the future value of the 6 annual deposits of $1500 at 8%:
F=1500(1.08^6-1)/(0.08)=11003.89
Since the last payment is due on the day of withdrawal, he would have paid $1500 to get back $11003.89, i.e. with an excess of 1003.89.
Therefore his last payment is 1500-1003.89=$496.11
4(25-1)
4(24)=96
Do parentheses first before other operations.
No, The base of a circle would be the area of the circle or the circle itself (top or bottom) of the cylinder
32. given (0,3)
fond slope by formula y2-y1/x2-x1 with any two points in the table ( you are lucky to be able to use formula in this equation!!) 5.3-3/1-0
2.3/1= 2.3 is slope you are able to check if this is true by doing it with every (x,y) point they give you.. luckyly the slope holds true for all the equation is
y=2.3x+3
33. this one the way I did it was plugging in (x,y) onto each equation and see of any hold true
y=4x+2.1
y=4x^2+2.1
y=2.1×4^x
y=4x
Let's plug in (1,8.4)
8.4=4 (1)+2.1
8.4=4+2.1
8.4=6.1 not true
8.4=4 (1)^2+2.1
8.4=4+2.1
8.4=6.1 not true
8.4=2.1×4^1 (1)
8.4=2.1×4
8.4=8.4 TRUE
8.4=4 (1)
8.4=4 not true
<h3>
Answer: Choice A</h3>
Explanation:
Label the three points as
P = (2,1)
Q = (5,1)
R = (6,1)
If you were to apply the slope formula for segment PQ, then you should get m = 0. If you computed the slope of segment QR, you should also get m = 0. The same goes for segment PR.
The fact we get the same slope each time tells us we have a straight line.
A visual approach is to plot the three points. They are all on the same straight line.