Answer:
Percent ionic character is defined as the ratio of a bond’s actual dipole moment to the dipole moment it would have if the electron were completely transferred from one atom to the other, multiplied by 100
Explanation:
The percent ionic character seeks to establish the amount of electrovalency in a particular compound. It simply compares the covalency i.e extent of shared electrons to the the electrons that are transferred.
It is given as the ratio of the acutal dipole moment to the dipole moment due to ionic character of the bond multiplied by 100:
Percent ionic character = μ_obs/μ_ionic x 100
Where μobs is the actual dipole moment and μ ionic is the dipole moment if the bonds were 100% ionic.
A hidden virus hides out inside the host cell for a time before it becomes active. An example of this is a cold sore on your lip.
Answer:
The concentration of the acid is about 0.114 M (option E)
Explanation:
Step 1: Data given
Volume of the monoprotic acid = 25.0 mL = 0.025 L
Molarity of the monoprotic acid = ?
Molarity of the NaOH solution = 0.115 M
Volume NaOH = 24.8 mL = 0.0248 L
Step 2: Calculate the concentration
a*Cb * Vb = b * Ca * Va
⇒ a = the coeficient of NaOH = 1
⇒ Cb = the molarity of the acid = TO BE DETERMINED
⇒ Vb = the volume of the acid = 0.025 L
⇒ b = the coefficient of the acid = monoprotic = 1
⇒ Ca = the moalrity of NaOH = 0.115 M
⇒ Va = the volume of NaOH = 0.0248 L
1 * Cb * 0.025 = 1 * 0.115 * 0.0248
0.025 Cb = 0.002852
Cb = 0.11408 M
The concentration of the acid is about 0.114 M
Amount of a substance (called the solute) that dissolves in a unit volume of a liquid substance (called the solvent) to form a saturated solution under specified conditions of temperature and pressure. Solubility is expressed usually as moles of solute per 100 grams of solvent.
