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AlekseyPX
2 years ago
7

Can someone solve and explain how to do these absolute equations for 40 points? I'll give brainliest to the best correct answer.

Mathematics
1 answer:
irga5000 [103]2 years ago
4 0

Answer:

Explanation Below

Step-by-step explanation:

1.    -4 + | x - 1 | = 3

= -4 + | x - 1 | + 4 = 3 + 4

= | x - 1 | = 7

= x - 1 = -7     or    x - 1 = 7

= x = -6 or x = 8

2.   6 + 4 | 2x + 6| = 14

 = 6 + 4 | 2x + 6 | - 6 = 14 - 6

 = 4 | 2x + 6 | = 8

 = 4 | 2x + 6 | / 4 = 8/4

 = 2x + 6 = -2          or         2x + 6 = 2

 = x = -4    or     x = -2

3.  -10 + | -6 - x | = 1

  = -10 + | -6 + x | + 10 = 1 + 10

  = | -6 - x | = 11

  =  -6 - x = -11     or   -6 - x = 11

  = x = -17        or       x = 5

4.    | 7 - 2x | + 4 = 5

   = | 7 - 2x | + 4 - 4 = 5 - 4

   = | 7 - 2x | = 1

   = 7 - 2x = -1            or             7 - 2x = 1

   = x = 3       or   x = 4

Here are the Steps:

SOLVING EQUATIONS CONTAINING ABSOLUTE VALUE(S)

Step 1: Isolate the absolute value expression.

Step2: Set the quantity inside the absolute value notation equal to + and - the quantity on the other side of the equation.

Step 3: Solve for the unknown in both equations.

Step 4: Check your answer analytically or graphically.

Hopes this Helps :D

Mark me Brainliest : )

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Substitute n =1, 2, 3, 4, 5 to get the first five terms.

Step-by-step explanation:

(4). $ g_n  = 2 . 3^{n - 1} $

To find the first term, substitute n = 1.

Therefore, $ g_1 = 2 . 3^{1 - 1} = 2 . 3^{0} = 2 . 1  $ = 2

$g_2 = 2 . 3^{2 - 1} = 2 . 3 $ = 6

$ g_3 =  2 . 3^{3 - 1} = 2 . 3^{2} = 2 . 9 $ = 18

$ g_4 = 2 . 3^{4  - 1} = 2 . 3^{3} = 2 . 27 $ = 54

$ g_5 =  2 . 3^{5 - 1} = 2 . 3^{4} = 2 . 81 $ = 168

Therefore the first five terms of the sequence are: 2, 6, 18, 54, 168.

(5). $ t_n = \frac{2}{3}t_{n - 1} $

$ t_2 = \frac{2}{3} t_{2 - 1} = \frac{2}{3}t_1  = \frac{2}{3}6 $ = 4

$ t_3 = \frac{2}{3} t_2 = \frac{2}{3}. 4 = \frac{8}{3} $

$ t_4 = \frac{2}{3}t_3 = \frac{2}{3}\frac{8}{3} = \frac{16}{9} $

$ t_5 = \frac{2}{3}t_4 = \frac{2}{3}\frac{16}{9} = \frac{32}{27} $

Therefore the first five terms in the sequence are: 6, 4, 8/3, 16/9, 32/27.

8 0
3 years ago
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