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2 years ago

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7. A man with blood type A marries a woman with blood type A. Their first child has blood type o

1 answer:

Stolb23 [73]2 years ago

7 0

Answer:

The answer is The letter A because I did this question before

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Which laboratory finding is a characteristic feature in a client with hypercortisolism?

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<span>Glucose metabolism is disturbed by hypercortisolism and the client's fasting blood glucose is increased. The client also has decreased serum potassium level. Since cortisol is an immunosuppressant, it lowers the immune system by lowering the lymphocyte count. </span>

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3 years ago

A hummingbird sucking nectar from a flower is an example of .......?

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2 years ago

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Which of the following could be a sequence in the carbon cycle?

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3 years ago

small group of 100 people decide to isolate themselves from the world and move to a small and remote deserted island. Out of thi

irina [24]

Answer:

Frequency of p $= 0.684$

Frequency of p $= 0.316$

Number of individuals with homozygous dominant (AA) $= 47$

Number of individuals with heterozygous (Aa) $= 43$

Number of individuals with homozygous recessive (aa) $= 10$

Explanation:

Out of 100 people, 10 have albino skin (aa)

So, the frequency of homozygous recessive individuals $(q^{2})$ is $\frac{10}{100} = 0.1$

Now, q will be

$= \sqrt{q^{2} } = \sqrt{0.1} \\= 0.316$

As per Hardy Weinberg's equation -

$p + q = 1$

Substituting the value of q in above equation, we get -

$p + 0.316 = 1p = 1 -0.316\\p = 0.684$

Now the frequency of homozygous dominant (AA) will be

$p^{2} = 0.684^{2} \\= 0.467$

Hence, out of 100 people $0.467 * 100 = 46.7 or 47$ people are homozygous dominant (AA)

Like wise out of 100 people $0.1 * 100 = 10$ people are homozygous recessive (aa)

As per As per Hardy Weinberg's equation-

$p^{2} + q^{2} + 2pq = 1\\$

Substituting the values in above equation, we get -

$0.467 + 0.316 + 2pq = 1\\2pq = 1 -( 0.467+ 0.1)\\2pq = 0.433$

So, out of 100 people $0.433 * 100 = 43.3 or 43$ people are heterozygous (Aa)

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3 years ago

In addition to highly repeated DNA sequences and unique (single-copy) DNA sequences, a third class of DNA exists. What is it cal

Ratling [72]

Answer:

long-read sequencing

Explanation:

a method of dna sequencing under active development

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2 years ago