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Eva8 [605]
3 years ago
12

A car, which started at rest, took 5.8 seconds to reach a velocity of 2km/s. What is

Physics
1 answer:
Allisa [31]3 years ago
3 0

Answer:

1 m/s

Explanation:

Use SUVAT and the equations of motion:

S

U = 0 km/s since it started at rest.

V = 2 km/s

A

T = 5.8 seconds

Equation used: v=\frac{v+u}{2}

v=\frac{2+0}{2}

v=1

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Let the displacement function of a particle is x(t)=(20t^2-15t+200). Find the total displacement, instantaneous velocity and ins
irga5000 [103]

Answer:

A.) 39.5 m

B.) 0

C.) 60m/s^2

Explanation:

Given that a displacement function of a particle is x(t)=(20t^2-15t+200).

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Reduce everything by dividing them by 5

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X(t) = 4(0.25)^2 - 3(0.25) + 40

X(t) = 0.25 - 0.75 + 40

Total displacement = 39.5 m

To calculate instantaneous velocity, substitute t into equation (2)

V = 60 (0.25) - 15

V = 0.

and to find instantaneous acceleration, differentiate dv/dt

dv/dt = 60

Therefore, acceleration = 60 m/s^2

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