Time it takes the projectile to hit the ground after being thrown up:
√h/1/2a
√8/(.5)(9.81)
√8/4.905
√1.630988787
= 1.277101714
= 1. 28
hope this helps :)
Answer:
d.none
Explanation:
because shape size and physical actually do are dependant
Answer:
The speed of the ball was, v = 3 m/s
Explanation:
Given data,
The time period of the ball, t = 8 s
The distance the ball rolled, d = 24 m
The velocity of an object is defined as the object's displacement to the time taken. The formula for the velocity is,
v = d / t m/s
Substituting the given values in the above equation,
v = 24 / 8
= 3 m/s
Hence, the speed of the ball was, v = 3 m/s
The answer is A. Or the first option. Pressure is changed by lowering the pressure, not reducing the volume. You would assume its C but its A.
The Earth’s average orbital speed expressed in kilometers per hours is 107225.5 Km/hr and the mass of the sun is 2.58 x
Kg
<h3>
Relationship between Linear and angular speed</h3>
Linear speed is the product of angular speed and the maximum displacement of the particle. That is,
V = Wr
Where
Given that the earth orbits the sun at an average circular radius of about 149.60 million kilometers every 365.26 Earth days.
a) To determine the Earth’s average orbital speed, we will make use of the below formula to calculate angular speed
W = 2
/T
W = (2 x 3.143) / (365.26 x 24)
W = 6.283 / 876624
W = 7.2 x
Rad/hr
The Earth’s average orbital speed V = Wr
V = 7.2 x
x 149.6 x 
V = 107225.5 kilometers per hours.
b) Based on the information given in this question, to calculate the approximate mass of the Sun, we will use Kepler's 3rd law
M = (4
) / G
M = (4 x 9.8696 x 3.35 x
) / (6.67 x
x 7.68 x
<em>)</em>
<em>M = 1.32 x </em>
/ 51.226
M = 2.58 x
Kg
Therefore, the Earth’s average orbital speed expressed in kilometers per hours is 107225.5 Km/hr and the mass of the sun is 2.58 x
Kg
Learn more about Orbital Speed here: brainly.com/question/22247460
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