A spring balance attempts to drag an object across a table, but the object does not move because of the force of friction acting
1 answer:
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Answer:
Option C: Third Class
Explanation:
This is third class because the effort or the input force is in the middle between the fulcrum and the load.
Using the formula:
w = m x g ....... eq1
here w is weight of the object.
m is mass of the object, and
g is the acceleration of gravity.
mass, m = 14 lbm (given)
acceleration of gravity, g= 32.0 ft/
Now, substituting the values in equation (1):
w = 14lbm x 32.0 ft/ = 448 lbm ft/
since, 1 lbf = 32.174 lbm ft/
so, w = 448 x
w = 13.924lbf
Hence, the mass of an object is 13.924 lbf.
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Answer:
Explanation:
The expression which represent the first diffraction minima by a circular aperture is given by --------eqn 1
The angle through which the first minima is diffracted is given by ---------eqn 2
As is very small so we can write
So from eqn 1 and eqn 2 we can write
--------eqn 3
Here is the position of first maxima D is the distance of screen from the circular aperture d is the diameter of aperture
It is given that diameter of circular aperture is 14.7 cm so
Now putting all these value in eqn 3