Answer:6.0×10^5m/s
Explanation:
According to the law of conservation of momentum, sum of the momenta of the bodies before collision is equal to the sum of their momenta after collision.
After their collision, the two bodies will move with a common velocity (v)
Momentum = mass × velocity
Let m1 be the mass of the proton = m
Let m2 be the mass of the alpha particle = m2
Let v1 be the velocity of the proton = 3.0×10^6m/s
Let v2 be the velocity of the alpha particle = 0m/s (since the body is at rest).
Using the law,
m1v1 + m2v2 = (m1 + m2)v
m(3.0×10^6) + 4m(0) = (m + 4m)v
m(3.0×10^6) = 5mv
Canceling 'm' at both sides,
3.0×10^6 = 5v
v = 3.0×10^6/5
The common velocity v = 6.0×10^5m/s
If a car crashes into another car like this, the wreck should go nowhere. Besides this being an unrealistic question, the physics of it would look like this:
Momentum before and after the collision is conserved.
Momentum before the collision:
p = m * v = 50000kg * 24m/s + 55000kg * 0m/s = 50000kg * 24m/s
Momentum after the collision:
p = m * v = (50000kg + 55000kg) * v
Setting both momenta equal:
50000kg * 24m/s = (50000kg + 55000kg) * v
Solving for the velocity v:
v = 50000kg * 24m/s/(50000kg + 55000kg) = 11,43m/s
This term absolute location refers to using another location as a reference point, rather than using latitude and longitude.
Answer:
single replacement reaction