Answer:
-150 kg m/s
Explanation:
The change of momentum is calculated as ;
Δp= m*Δv where
where
Δp= change in momentum
Δv = vf-vi
m= mass of the object
Change in momentum is also calculated when using the formula;
Δp = F * Δt when F is the net force applied and Δt is the time of action.
In this case;
m= 15 kg
vf= -10 m/s
vi= 0 m/s
Taking rightward direction to be positive, then leftward will be negative.
Applying the formula as;
Δp = m*Δv
Δp = 15 * { -10 -0} = 15*-10 = -150 kg m/s
Answer:
28 moles of X.
Explanation:
Let's consider the complete combustion of ethanol.
C₂H₆O(l) + 3 O₂(g) ⇒ 2 CO₂(g) + 3 H₂O(l)
When 1 mole of ethanol burns it releases 1370 kJ, that is, the enthalpy of combustion is -1370 kJ/mol. If the energy released by one mole of etanol were used to syntesize the compound X, it would take 45.9 kJ to form 1 mole of X, that is, the enthalpy of formation is -49.5 kJ/mol. Then,
<span>The thermal energy is the work done by friction. If Justin is at rest intially, his potential energy is MGH. Hence we have 30* 9.8*8 = 2352N. Where m is mass, g accleration due to gravity, and h is the height. When he gets to the bottom of the slide, his potential energy is converted to usable kinetic energy, so we have 1/2 mv^2. We end up with 1/2 * 30 * (11)^2 = 1815N. He started with 2352N and ended up with 1815N. Hence the thermal energy is 2352 - 1815 = 537N.</span>
Answer:
Th steps is as shown in the attachment
Explanation:
from the diagram, its indicates that twelve identical charges are distributed evenly on the circumference of the circle. assuming one of gthe charge is shifted to the centre of he circle alomng the x axis, as such the charge is unbalanced and there is need ot balanced all the identical charges for the net force to be equal to zero.
The mathematical interpretation is as shown in the attachment.
Answer: q=5.70 x 10^13 C
Explanation:
gravitational attraction = electrostatic repulsion GMm/d^2 = kQ^2/d^2 as you can see the d^2 cancel out. that is why lunar distance is irrelevant. G is the universal gravitational constant = 6.67 x 10^-11 m^3 / kgs^2 M is earth's mass = 5.972 × 10^24 kg m is moon's mass = 7.342×10^22 kg Q is charge on earth and moon. k is coulomb's constant = 9 x10^9 N m^2 /C^2 On solving equation for Q. Q = sqrt (GMm/k) = sqrt ( 6.67 x 10^-11 x 5.972 x 10^24 * 7.342×10^22 / 9 x10^9) = 5.70 x 10^13 C
