All categories

2 years ago

A chemical lab isolates a metallic element from a compound. Tests of

1 answer:

6 0

The isolated metallic element that has 4 electrons in its outer shell will most likely be found in group 14.

<h3>Periodic Table of elements </h3>

The periodic table of elements is a table which arranges elements based on their electronic configurations.

Elements with the same number of valence electrons are arranged into the same group
Elements with the same number of electron shells are arranged in periods.

Elements in group 14 have four valence electrons
Elements in group 2 have two valence electrons
Elements in group 15 have five valence electrons
Elements in group 3 have three valence electrons.

Therefore, the isolated metallic element that has 4 electrons in its outer shell will most likely be found in group 14.

Learn more about Periodic Table of elements at: brainly.com/question/14514242

You might be interested in

A test of the prototype of a new automobile shows that the minimum distance for a controlled stop from 95 km/h to zero is 55 m.

iris [78.8K]

Answer:

-0.64525g

Explanation:

t = Time taken for the car to stop

u = Initial velocity = 95 km/h

v = Final velocity = 0 km/h

s = Displacement

a = Acceleration

Equation of motion

$v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-95^2}{2\times 0.055}\\\Rightarrow a=-82045.45\ km/h^2$

Converting to m/s²

$a=82045.45=\frac{82045.45\times 1000}{3600\times 3600}=-6.33\ m/s^2$

g = Acceleration due to gravity = 9.81 m/s²

Dividing both the accelerations, we get

$\frac{a}{g}=\frac{-6.33}{9.81}=-0.64525\\\Rightarrow a=-0.64525g$

Hence, acceleration of the car is -0.64525g

8 0

4 years ago

You're driving down the highway late one night at 21 m/s when a deer steps onto the road 35 m in front of you. Your reaction tim

andreev551 [17]

Speed with which initially car is moving is 21 m/s

Reaction time = 0.50 s

distance traveled in the reaction time d = v t

d = 21 * 0.50 = 10.5 m

deceleration after this time = -10 m/s^2

now the distance traveled by the car after applying bakes

$v_f^2 - v_i^2 = 2a d$

$0 - 21^2 = 2(-10)d$

$d = 22.05 m$

so total distance moved before it stop

d = 22.05 + 10.5 = 32.55 m

so the distance from deer is 35 - 32.55 = 2.45 m

now to find the maximum speed with we can move we will assume that we will just touch the deer when we stop

so our distance after brakes are applied is d = 35 - 10.5 = 24.5 m

again by kinematics

$v_f^2 - v_i^2 = 2 ad$

$0 - v^2 = 2(-10)(24.5)$

$v = 22.1 m/s$

so maximum speed would be 22.1 m/s

5 0

3 years ago

An object has an acceleration of 12.0 m/s/s. If the mass of this object were tripled (with no change in its net force), then its

yaroslaw [1]

Answer:

If it is triple it means we multiply it by 3 then it is 36.3 m/s/s

8 0

3 years ago

A man of mass 85 kg runs up a flight of stairs of height 4.6 m in a time period

seraphim [82]

Explanation:

a) Power = work / time = force × distance / time

P = Fd/t

P = (85 kg × 9.8 m/s²) (4.6 m) / (12 s)

P ≈ 319 W

b) P = Fd/t

0.70 (319 W) = (m × 9.8 m/s²) (4.6 m) / (9.6 s)

m = 47.6 kg

7 0

3 years ago

does the wavelength of the sound increase, decrease, or stay the smae as the musician changes from the first sound to the second

Naya [18.7K]

Decrease K k kk kk k k k

8 0

3 years ago

Read 2 more answers