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Maurinko [17]
3 years ago
12

A single covalent bond forms when two atoms do which of these?

Physics
2 answers:
In-s [12.5K]3 years ago
7 0

Answer:

A single covalent bond is formed when two atoms <u><em>share a pair of electrons.</em></u>

Explanation:

Valencia electrons are the electrons found in the last electronic layer (called valence orbitals). These electrons are what determine the ability of the atom to form bonds. When an element joins another, it does so through its valence electrons.

The covalent bond is the chemical bond between atoms where electrons are shared, forming a molecule. Covalent bonds are established between non-metallic elements, such as hydrogen H, oxygen O and chlorine Cl. These elements have many electrons in their outermost level (valence electrons) and have a tendency to gain electrons to acquire the stability of the electronic structure of noble gas. The shared electron pair is common to the two atoms and holds them together.

In a simple covalent bond, each atom brings an electron to the bond, that is, a pair of electrons is shared between two atoms.

In a double covalent bond, each atom brings two electrons to the bond, that is, two pairs of electrons are shared between two atoms.

Finally, in a triple covalent bond, each atom brings three electrons to the bond, that is, three pairs of electrons are shared between two atoms.

Then, <u><em> a single covalent bond is formed when two atoms share a pair of electrons.</em></u>

marissa [1.9K]3 years ago
6 0
When atoms bond by sharing electrons<span>, it is called a covalent bond. One pair of shared </span>electrons<span> is a single covalent bond. Two shared pairs is a double covalent bond, and three shared pairs is a triple covalent bond.</span>
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An fm radio station broadcasts at 98. 6 mhz. What is the wavelength of the radiowaves?.
victus00 [196]

The wavelength of the radio waves is 3.04 cm.

<h3>Calculation:</h3>

λf = c

λ = c/f

where,

λ = wavelength

c = speed of light

f = frequency

Given,

f = 98.6 MHz = 98.6 × 10⁶

c = 3 × 10⁸

To find,

λ =?

Put the values in the formula,

λ = c/f

λ = 3 × 10⁸/98.6 × 10⁶

  = 0.0304 × 10²  m

  = 3.04 cm

Therefore, the wavelength of the radio waves is 3.04 cm.

Learn more about the calculation of wavelength here:

brainly.com/question/8422432

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3 0
2 years ago
Help me , what is the properties of fluids ? ​
rodikova [14]
Some of the most fundamental concepts of fluid properties are temperature, density, and composition.
4 0
3 years ago
Read 2 more answers
Two long, straight wires are separated by 0.120 m. The wires carry currents of 11 A in opposite directions, as the drawing indic
rewona [7]

Answer:

The magnitude of the magnetic field is 1.83 x 10^{-5} T.

Explanation:

The flow of an electric current in a straight wire induces magnetic field around the wire. When current is flowing through two wires in the same direction, a force of attraction exists between the wires. But if the current flows in opposite directions, the force of repulsion is felt by the wires.

In the given question, the direction of flow of current through the wires is opposite, thus both wires applies the same field on each other. The result to repulsion between them.

The magnetic field (B) between the given wires can be determined by:

B = \frac{U_{o}I }{2\pi r}

where: I is the current, r is the distance between the wires and U_{0} is the magnetic field constant.

But, I = 11 A, r = 0.12 m and U_{0} = 4\pi x 10^{-7} Tm/A

So that;

B = \frac{4\pi *10^{-7}*11 }{2\pi *0.12}

   = 1.8333 x 10^{-5}

B = 1.83 x 10^{-5} T

6 0
3 years ago
What is the velocity of an object that has a momentum of 4,000 kg-m/s and a mass of 115 kg? Round to the nearest hundredth.
iren [92.7K]

Answer:

B. 34.78 m/s

Explanation:

Momentum of a body or an object is given as the product of its velocity and its mass.

Therefore;

Momentum= velocity x mass

But; velocity = ? mass =115 kg , momentum = 4,000 kgm/s

Thus; velocity= momentum/mass

                      = 4,000/115

                       = 34.78 m/s

6 0
3 years ago
You have a 160-Ω resistor and a 0.430-H inductor. Suppose you take the resistor and inductor and make a series circuit with a vo
S_A_V [24]

Answer:

A.  Z = 185.87Ω

B.  I  =  0.16A

C.  V = 1mV

D.  VL = 68.8V

E.  Ф = 30.59°

Explanation:

A. The impedance of a RL circuit is given by the following formula:

Z=\sqrt{R^2+\omega^2L^2}       (1)

R: resistance of the circuit = 160-Ω

w: angular frequency = 220 rad/s

L: inductance of the circuit = 0.430H

You replace in the equation (1):

Z=\sqrt{(160\Omega)^2+(220rad/s)^2(0.430H)^2}=185.87\Omega

The impedance of the circuit is 185.87Ω

B. The current amplitude is:

I=\frac{V}{Z}                     (2)

V: voltage amplitude = 30.0V

I=\frac{30.0V}{185.87\Omega}=0.16A

The current amplitude is 0.16A

C. The current I is the same for each component of the circuit. Then, the voltage in the resistor is:

V=\frac{I}{R}=\frac{0.16A}{160\Omega}=1*10^{-3}V=1mV            (3)

D. The voltage across the inductor is:

V_L=L\frac{dI}{dt}=L\frac{d(Icos(\omega t))}{dt}=-LIsin(\omega t)\\\\V_L=-(0.430H)(160\Omega)sin(220 t)=68.8sin(220t)\\\\V_L_{max}=68.8V

E. The phase difference is given by:

\phi=tan^{-1}(\frac{\omega L}{R})=tan^{-1}(\frac{(220rad/s)(0.430H)}{160\Omega})\\\\\phi=30.59\°

5 0
3 years ago
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