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Maurinko [17]
3 years ago
12

A single covalent bond forms when two atoms do which of these?

Physics
2 answers:
In-s [12.5K]3 years ago
7 0

Answer:

A single covalent bond is formed when two atoms <u><em>share a pair of electrons.</em></u>

Explanation:

Valencia electrons are the electrons found in the last electronic layer (called valence orbitals). These electrons are what determine the ability of the atom to form bonds. When an element joins another, it does so through its valence electrons.

The covalent bond is the chemical bond between atoms where electrons are shared, forming a molecule. Covalent bonds are established between non-metallic elements, such as hydrogen H, oxygen O and chlorine Cl. These elements have many electrons in their outermost level (valence electrons) and have a tendency to gain electrons to acquire the stability of the electronic structure of noble gas. The shared electron pair is common to the two atoms and holds them together.

In a simple covalent bond, each atom brings an electron to the bond, that is, a pair of electrons is shared between two atoms.

In a double covalent bond, each atom brings two electrons to the bond, that is, two pairs of electrons are shared between two atoms.

Finally, in a triple covalent bond, each atom brings three electrons to the bond, that is, three pairs of electrons are shared between two atoms.

Then, <u><em> a single covalent bond is formed when two atoms share a pair of electrons.</em></u>

marissa [1.9K]3 years ago
6 0
When atoms bond by sharing electrons<span>, it is called a covalent bond. One pair of shared </span>electrons<span> is a single covalent bond. Two shared pairs is a double covalent bond, and three shared pairs is a triple covalent bond.</span>
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Physics Homework MathPhys homie if you see this pls help
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Answer:

1. -8.20 m/s²

2. 73.4 m

3. 19.4 m

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1. Apply Newton's second law to the car in the y direction.

∑F = ma

N − mg = 0

N = mg

Apply Newton's second law to the car in the x direction.

∑F = ma

-F = ma

-Nμ = ma

-mgμ = ma

a = -gμ

Given μ = 0.837:

a = -(9.8 m/s²) (0.837)

a = -8.20 m/s²

2. Given:

v₀ = 34.7 m/s

v = 0 m/s

a = -8.20 m/s²

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v² = v₀² + 2aΔx

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3. Since your braking distance is the same as the car in front of you, the minimum safe following distance is the distance you travel during your reaction time.

d = v₀t

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d = 19.4 m

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3 years ago
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