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4 years ago

The boundaries between all of these plates are best described as the sites of

1 answer:

4 0

The correct answer should be Fault lines. These are lines that occur at boundaries of tectonic plates and they can either be convergent meaning that the plates move towards each other or they can be divergent meaning that the plates move away from each other. They can also just rub against each other and cause things like earthquakes.

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a person rearranging their living furniture expends 350 J of energy to push a coach 4.5 m across their living room calculate the

sergiy2304 [10]

1575 N

Explanation:

Step 1:

Let us consider that 350 J of energy is spent by that person to push a couch to 4.5 m from its initial position.

Let F be the force required and E be the energy spent and D be the distance traveled by the couch from its initial state.

In Physics, Work done = Force / Displaced distance

Step 2:

Let the work done be 350 J and Distance be 4.5 m

Then Force exerted = $350*4.5 = 1575 N$

5 0

3 years ago

Definition: The energy transferred by a force to a moving object.

Marysya12 [62]

Answer:

Force applied

Explanation:

An object will remain at its state of rest unless a non zero for act on it

6 0

3 years ago

7. A 1.0 kg metal head of a geology hammer strikes a solid rock with a velocity of 5.0 m/s. Assuming all the energy is retained

marta [7]

The increase in temperature of the metal hammer is 0.028 ⁰C.

The given parameters:

mass of the metal hammer, m = 1.0 kg
speed of the hammer, v = 5.0 m/s
specific heat capacity of iron, 450 J/kg⁰C

The increase in temperature of the metal hammer is calculated as follows;

$Q = K.E\\\\mc \Delta T = \frac{1}{2} mv^2\\\\\Delta T = \frac{v^2}{2 c}$

where;

c is the specific heat capacity of the metal hammer

Assuming the metal hammer is iron, c = 450 J/kg⁰C

$\Delta T = \frac{5^2}{2 \times 450} \\\\\Delta T = 0.028 \ ^0C$

Thus, the increase in temperature of the metal hammer is 0.028 ⁰C.

Learn more about heat capacity here: brainly.com/question/16559442

8 0

3 years ago

Activity log - Standing Whole Body Record your time and activity below and in your unit fitness log. If a particular category do

sasho [114]

Answer:

Date: N/A

Warm-up: 5 minutes

Cool-down: 6 minutes

Type of Activity: Cardiovascular

Description of Activity and Time: Running in place for 10 minutes

Intensity Level: Moderate

Total Time: 21 minutes

Explanation: Mark me as brainiest hope this helps I just did it

6 0

4 years ago

Hooke's law describes an ideal spring. Many real springs are better described by the restoring force (F Sp ) s =−kΔs−q(Δs) 3 (p)

Montano1993 [528]

Answer with Explanation:

We are given that

Restoring force, $(FS_p)s=-k\Delta s-q(\Delta s)^3$

$k=350N/m$

$q=750 N/m^3$

We have to find the work must you do to compress this spring 15 cm.

$\Delta s=15 cm=0.15 m$

Using 1 m=100 cm

Work done= $\int_{0}^{0.15}-Fd(\Delta s)$

W= $-\int_{0}^{0.15}(-k\Delta s-q(\Delta s)^3))d(\Delta s)$

$W=k[\frac{(\Delta s)^2}{2}]^{0.15}_{0}+q[\frac{(\Delta s)^4}{4}]^{0.15}_{0}$

$W=0.01125k+0.000127q=0.01125\times 350+0.000127\times 750$

$W=4.033 J$

Ideal spring work= $0.5k(\Delta s)^2=0.5\times 350\times (0.15)^2=3.938 J$

Percentage increase in work= $\frac{4.033-3.938}{3.928}\times 100=2.4$ %

6 0

4 years ago