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aliina [53]
3 years ago
9

Using a skillet on the stove to cook scrambled eggs is an example of which heat transfer?

Physics
2 answers:
MatroZZZ [7]3 years ago
4 0

Answer: conduction.


Explanation:


1) A skillet or pan will be in direct contact with the food.


2) Being the skillet a solid matter, it transfers heat by conduction.


3) There are three heat transfer mechanisms: convection, conduction, radiation.


i) Convection: only happens in fluids: liquids and gases.


It is a slow mechanism and is due to the motion of the particles of fluid.


This is not the case, since the skillet is solid and the eggs are in direct contact with it. If the eggs were separated from the skillet convection might happen but it would be very slow and the eggs would take so long time to be cooked.


ii) Conduction: happens by direct contact among neighboring particles, due to their vibrations. The vibrations are only transmitted to neighboring particles, which is only possibble when they are in direct contact, so it is the classical mechanism in solids. So, the heat transfer using the skillet to cook scrambles eggs is an example of conduction.


iii) Radiation: is the transfer of heat by infrared waves. It is an important mechanism when the substances are separated by vaccum or gases and the difference of temperature is high. Yet, this is not the importante mechanism here. You feel heat radiation when you put your hand close to the skillet.



Nadusha1986 [10]3 years ago
4 0
Conduction i think hope i helped :)
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A laser beam enters a 12.0 cm thick glass window at an angle of 33.0° from the normal. The index of refraction of the glass is 1
Alenkinab [10]

Answer:

The time is 0.563 ns.

Explanation:

Given that,

Index of refraction of glass = 1.41

Distance = 12.0 cm

Angle = 33.0°

We need to calculate the refraction angle

Using Snell's law

n_{1}\sin\theta=n_{r}\sin\theta

put the value into the formula

1\times\sin33=1.41\sin\theta

\sin\theta=\dfrac{1\times\sin33}{1.41}

\theta=22.71^{\circ}

We need to calculate the velocity of beam in glass

Using formula of velocity

v=\dfrac{c}{n}

Put the value into the formula

v=\dfrac{3\times10^{8}}{1.41}

v=2.13\times10^{8}\ m/s

We need to calculate the time

Using formula of distance

v=\dfrac{d}{t}

t=\dfrac{12.0\times10^{-2}}{2.13\times10^{8}}

t=5.63\times10^{-10}\ sec

t=0.563\times10^{-9}\ sec

t=0.563\ ns

Hence, The time is 0.563 ns.

6 0
3 years ago
What is an example of transparent
nataly862011 [7]

Answer:

When something is transparent, it means that it allows light to pass through or is see-through . For example:

1) glass

2) air

3) some plastics

7 0
3 years ago
Read 2 more answers
50 points!!! Kinetics
iris [78.8K]

Answer:

98 m √

Explanation:

How about s = Vo * t + ½at² ?

s = h = Vo * 2s - 4.9m/s² * (2s)² = 2Vo - 19.6

and

h = Vo * 10s - 4.9m/s² * (10s)² = 10Vo - 490

Subtract 2nd from first:

0 = -8Vo + 470.4

Vo = 58.8 m/s

h = 58.8m/s * 2s - 4.9m/s² * (2s)² = 98 m

3 0
3 years ago
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A 62.00-cm guitar string under a tension of 70.000 N has a mass per unit length of 0.10000 g/cm. What is the highest resonant fr
quester [9]

Answer:

17,947.02 Hz

Explanation:

length (L) = 62 cm = 0.62 m

tension (T) = 70 N

mass per unit length (μ) = 0.10000 g/cm = 0.010000 kg/m

maximum frequency = 18,000 Hz

f = \frac{n}{2L} x \sqrt{\frac{T}{μ}}

f = \frac{n}{2 x 0.62} x \sqrt{\frac{70}{0.01} }

f = n x 67.47

18,000 = n x 67.47

n = 266.8≈ 266

the 267th overtone is the highest overtone that can be heard by this person, and its frequency would be 26 x 67.47 = 17,947.02 Hz

8 0
3 years ago
It takes 20s for 3x10^6 electrons to flow through a wire ,what is the current?
Elina [12.6K]

Answer:

Explanation:

The variables we know and are given are:

time, t = 20s

Charge, Q = 3x1-^-6 electrons, which is just 3x10^-6C (C stands for Coulombs, which is the unit for Charge)

We need to find the current, I, and since we know Q and t we can substitute these values into the given equation:

I=Q/t (which if you look at what the RHS is saying, its Charge over time, or more literally means the amount of charge passing a point over a period of time)

If we substitute these values, we will get I as:

I = Q / t

I = 3x10^-6 / 20

I = 1.5x10^-7 A

Hope this helps!

6 0
3 years ago
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