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statuscvo [17]
3 years ago
12

A particular power source releases kinetic energy that is used to move giant

Chemistry
2 answers:
Lisa [10]3 years ago
6 0

Answer: an electric generator

Explanation:

Shalnov [3]3 years ago
4 0

Answer:

a

Explanation:

ap e x :)

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Hello! Does anyone know how the structural formula of 2, 2 dimethyl butane is? Please help!<br><br>​
Alja [10]

Answer:

I have it.

Explanation:

3 0
3 years ago
How many grams of copper (I) chloride can be produced from the reaction of 73.5 g of copper (I) oxide with hydrochloric acid acc
natulia [17]

The balanced equation for the reaction is as follows

Cu₂O + 2HCl ---> 2CuCl + H₂O

Molar ratio of Cu₂O to CuCl is 1:2

mass of Cu₂O reacted - 73.5 g

Number of moles of Cu₂O reacted - 73.5 g / 143 g/mol = 0.51 mol

According to the molar ratio,

when 1 mol of  Cu₂O reacts then 2 mol of CuCl is formed

therefore when 0.51 mol of Cu₂O reacts then - 2 x 0.51 mol of CuCl is formed

number of CuCl moles formed - 1.02 mol

mass of CuCl formed - 1.02 mol x 99 g/mol = 101 g

mass of CuCl formed is 101 g

6 0
3 years ago
Which of the following is the best example of potential energy?
AveGali [126]

Answer:

A car stopped at the top of a hill

Explanation:

Potential energy is the energy that is stored in an object due to its position relative to some zero position.

therefore, the answer is the first option

=> A car stopped at the top of a hill

hope this helps and is right :)

3 0
2 years ago
Read 2 more answers
Olivia bought new gym shoes to play volleyball because she kept slipping when she ran in her old shoes. How will the new soles h
HACTEHA [7]
Maybe her old shoes had soft worn out bottoms and she slips in them. So her new shoes had more grip than her old ones so they kept her from falling.
6 0
3 years ago
Read 2 more answers
The reaction of hydrogen and iodine to produce hydrogen iodide has a Kc of 54.3 at 703 K. Given the initial concentrations of H2
pentagon [3]

Answer:

[HI] = 0.7126 M

Explanation:

Step 1: Data given

Kc = 54.3

Temperature = 703 K

Initial concentration of H2 and I2 = 0.453 M

Step 2: the balanced equation

H2 + I2 ⇆ 2HI

Step 3: The initial concentration

[H2] = 0.453 M

[I2] = 0.453 M

[HI] = 0 M

Step 4: The concentration at equilibrium

[H2] = 0.453 - X

[I2] = 0.453 - X

[HI] = 2X

Step 5: Calculate Kc

Kc = [Hi]² / [H2][I2]

54.3 = 4x² / (0.453 - X(0.453-X)

X = 0.3563

[H2] = 0.453 - 0.3563 = 0.0967 M

[I2] = 0.453 - 0.3563 = 0.0967 M

[HI] = 2X = 2*0.3563 = 0.7126 M

3 0
3 years ago
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