Select the correct answer from each drop-down menu. consider the substances hydrogen (h2), fluorine (f2), and hydrogen fluoride
1 answer:
The boiling point of HF is higher than the boiling point of , and it is higher than the boiling point of
.
The boiling point is the temperature at which the pressure exerted by the surroundings upon a liquid is equalled by the pressure exerted by the vapour of the liquid.
has weak dispersion force attractions between its molecules, whereas liquid HF has strong ionic interactions between
and
ions.
Only London Forces are formed - Therefore more energy is required to break the intermolecular forces in HF than in the other hydrogen halides and so HF has a higher boiling point.
and
will only have intra-molecular attractions and there will be no hydrogen bonds present in them. As a result, their boiling point will be lower.
Hence, the boiling point of HF is higher than the boiling point of , and it is higher than the boiling point of
.
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Answer: 0.0164 molar concentration of hydrochloric acid in the resulting solution.
Explanation:
1) Molarity of 0.250 L HCl solution : 0.0328 M
Moles of HCl in 0.250 L solution = 0.0082 moles
2) Molarity of 0.100 L NaOH solution : 0.0245 M
Moles of NaOH in 0.100 L solution = 0.00245 moles
3) Concentration of hydrochloric acid in the resulting solution.
0.00245 moles of NaOH will neutralize 0.00245 moles of HCl out of 0.0082 moles of HCl.
Now the new volume of the solution = 0.100 L +0.250 L = 0.350 L
Moles of HCl left un-neutralized = 0.0082 moles - 0.00245 moles = 0.00575 moles
Molarity of HCl left un-neutralized :
0.0164 molar concentration of hydrochloric acid in the resulting solution.