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kari74 [83]
4 years ago
15

Factor completely 2x4y3 − 12x3y2 − 8x2y.

Mathematics
2 answers:
MAVERICK [17]4 years ago
8 0

Answer:

2x^2y[x^{2}y^{2}-6xy-4]

Step-by-step explanation:

we have

2x^{4}y^{3}-12x^3y^2-8x^2y

Factor 2x^2y

so

2x^2y[x^{2}y^{2}-6xy-4]

Anvisha [2.4K]4 years ago
4 0

Answer:

Question: Factor completely 2x4y3 − 12x3y2 − 8x2y.

Possible Answer: A. 2x2y(x2y2 − 6xy − 4)

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