Answer:
6.3 × 10–^4
Explanation:
Hello there!
In this case, since the rate laws are written in terms of the rate constant and the concentration of the species contributing to the rate of reaction, as this one is second order in Xe and first order in F2, the rate law would be:
![r=k[Xe]^2[F_2]](https://tex.z-dn.net/?f=r%3Dk%5BXe%5D%5E2%5BF_2%5D)
Thus, by plugging in the rate constant and concentrations, we obtain:
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Answer:
See the answer below, please.
Explanation:
A precipitation reaction is defined as one that yields an insoluble compound (precipitate) as a product by mixing two different solutions. An example:
NaCl + AgN03 -> Agcl (precipitate) + NaN03
Answer:
Explanation:
Hello!
In this case, according to the ideal gas equation ratio for two states:
Whereas both n and R are cancelled out as they don't change, we obtain:
Thus, by solving for the final pressure, we obtain:
Now, since initial conditions are 1.00 atm, 273.15 K and 17 L and final temperature and volume are 94 + 273 = 367 K and 12 L respectively, the resulting pressure turns out to be:
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Answer:
B) an anion
Explanation:
During bonding atoms may share electron or give out electron . In the case of electrovalent or ionic bonding, electron(s) is/are transferred from one atom to another . The atom that donate the electron are known as donor atom and the atom that receives the electron are known as receivers.
The atom that donate the electron becomes a cation(positively charged) as it lose it electron(s) while the receiver gains electron to become an anion which is a negatively charge ion.
An example of such interaction is between a sodium atom and a chlorine atom. The Na atom lose it electron to become positively charged(cation) while the chlorine atom gains electron to become negatively charged(anion). Both atom bond together losing and gaining electron to fulfill the octet rule.
Na+ + Cl- → NaCl
The answer to yo question is ( it has three OH groups).
