Melting, vaporization, boiling, and sublimation.
1) Calcium carbonate contains 40.0% calcium by weight.
M(CaCO₃)=100.1 g/mol
M(Ca)=40.1 g/mol
w(Ca)=40.1/100.1=0.400 (40.0%)!
2) Mass fraction of this is excessive data.
3) The solution is:
m(Ca)=1.2 g
m(CaCO₃)=M(CaCO₃)*m(Ca)/M(Ca)
m(CaCO₃)=100.1g/mol*1.2g/40.1g/mol=3.0 g
One end has a specific binding site for a particular amino acid and the other end the sequence that can pair with a codon, called an anticodon. The DNA code is translated into messenger RNA when the RNA polymerase binds to it and makes the mRNA copy.
Answer:19.2
Explanation: if see you have to times it and show it with times