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3 years ago

1.* Write the name and symbol of the ion formed when

Chemistry

2 answers:

BartSMP [9]3 years ago

7 0

Answer:

Explanation:

a. When a sulphur atom gains two electrons, it becomes negatively charged to form an anion called sulphide ion and it’s represented as S2-.

b. When an aluminium atom loses three electrons, it becomes positively charged to form a cation and it is represented as Al3+.

c. When a nitrogen atom gains three electrons, it becomes negatively charged to form an anion called nitride ion and it is represented as N3-.

d. When a calcium atom loses two electrons, it becomes positively charged to form a cation and it is represented as Ca2+

• When Iron (Fe) loses two electrons, it becomes Fe2+ and the electronic configuration will be 1S2 2S2 2P6 3S2 3P6 3d6

• When Cobalt (Co) loses two electrons, it becomes Co2+ and the electronic configuration will be 1S2 2S2 2P6 3S2 3P6 3d7

• When Nickel (Ni) loses two electrons, it becomes Ni2+ and the electronic configuration will be 1S2 2S2 2P6 3S2 3P6 3d8

•When Chromium (Cr) loses three electrons, it becomes Cr3+ and the electronic configuration will be 1S2 2S2 2P6 3S2 3P6 3d3

• When Manganese (Mn) loses three electrons, it becomes Mn3+ and the electronic configuration will be 1S2 2S2 2P6 3S2 3P6 3d4

•Bromine (Br) gains an electron to become Br-

•Hydrogen (H) gains an electron to become H-

•Arsenic (As) gains three electrons to become As3-

•Selenium (Se) gains two electrons to become Se2-

wlad13 [49]3 years ago

6 0

1a) anion and S-2
1b) cation and Al+3
1c) anion and N-3
1d) cation and Ca+2

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shutvik [7]

Answer:

I really dont know i just guessed :(

Explanation:

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3 years ago

The decomposition of N2O4 into NO2 has Kp = 2. Some N2O4 is placed into an empty container, and the partial pressure of NO2 at e

Sunny_sXe [5.5K]

Answer: Option (B) is the correct answer.

Explanation:

Expression for the given decomposition reaction is as follows.

$N_{2}O_{4} \rightarrow 2NO_{2}$

Let us assume that x concentration of $N_{2}O_{4}$ is present at the initial stage. Therefore, according to the ICE table,

$N_{2}O_{4} \rightarrow 2NO_{2}$

Initial : x 0

Change : - 0.1 $2 \times 0.1$

Equilibrium : (x - 0.1) 0.2

Now, expression for $K_{p}$ of this reaction is as follows.

$K_{p} = \frac{P^{2}_{NO_{2}}}{P_{N_{2}O_{4}}}$

Putting the given values into the above formula as follows.

$K_{p} = \frac{P^{2}_{NO_{2}}}{P_{N_{2}O_{4}}}$

$2 = \frac{(0.2)^{2}}{(x - 0.1)}$

$2 \times (x - 0.1) = (0.2)^{2}$

x = 0.12

This means that $P_{N_{2}O_{4}}$ = x = 0.12 atm.

Thus, we can conclude that the initial pressure in the container prior to decomposition is 0.12 atm.

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3 years ago

at a given tempature gas with a pressure of 150 kpa has volume of 0.8 l if the pressure decreases to 75kpa and the temperature r

vova2212 [387]

<span>P*V/T=constant
so P*V= constant*T
if T doesn't change then
P*V= constant
so 150kPa*0.8L=75kPa*xL
xL=150kPa*0.8L/75kPa=1.6L
hope it help</span>

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3 years ago

The molecule NH3 contains all single bonds.<br><br> true <br> false

dsp73

<h3><u>Answer;</u></h3>

True

<h3><u>Explanation</u>;</h3>

The molecule NH3 contains all single bonds.
NH3 has a three single covalent bond among its nitrogen and hydrogen atoms,because one valence electron of each of three atom of hydrogen is shared with three electron.
There are three covalent bonds are in NH3 . Each hydrogen make a single bond with nitrogen and there is also a pair of electron which is unpaired from nitrogen.

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3 years ago

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