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3 years ago

1.* Write the name and symbol of the ion formed when

Chemistry

2 answers:

BartSMP [9]3 years ago

7 0

Answer:

Explanation:

a. When a sulphur atom gains two electrons, it becomes negatively charged to form an anion called sulphide ion and it’s represented as S2-.

b. When an aluminium atom loses three electrons, it becomes positively charged to form a cation and it is represented as Al3+.

c. When a nitrogen atom gains three electrons, it becomes negatively charged to form an anion called nitride ion and it is represented as N3-.

d. When a calcium atom loses two electrons, it becomes positively charged to form a cation and it is represented as Ca2+

• When Iron (Fe) loses two electrons, it becomes Fe2+ and the electronic configuration will be 1S2 2S2 2P6 3S2 3P6 3d6

• When Cobalt (Co) loses two electrons, it becomes Co2+ and the electronic configuration will be 1S2 2S2 2P6 3S2 3P6 3d7

• When Nickel (Ni) loses two electrons, it becomes Ni2+ and the electronic configuration will be 1S2 2S2 2P6 3S2 3P6 3d8

•When Chromium (Cr) loses three electrons, it becomes Cr3+ and the electronic configuration will be 1S2 2S2 2P6 3S2 3P6 3d3

• When Manganese (Mn) loses three electrons, it becomes Mn3+ and the electronic configuration will be 1S2 2S2 2P6 3S2 3P6 3d4

•Bromine (Br) gains an electron to become Br-

•Hydrogen (H) gains an electron to become H-

•Arsenic (As) gains three electrons to become As3-

•Selenium (Se) gains two electrons to become Se2-

wlad13 [49]3 years ago

6 0

1a) anion and S-2
1b) cation and Al+3
1c) anion and N-3
1d) cation and Ca+2

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Answer : The final volume of gas will be, 26.3 mL

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 0.974 atm

$P_2$ = final pressure of gas = 0.993 atm

$V_1$ = initial volume of gas = 27.5 mL

$V_2$ = final volume of gas = ?

$T_1$ = initial temperature of gas = $22.0^oC=273+22.0=295K$

$T_2$ = final temperature of gas = $15.0^oC=273+15.0=288K$

Now put all the given values in the above equation, we get:

$\frac{0.974 atm\times 27.5 mL}{295K}=\frac{0.993 atm\times V_2}{288K}$

$V_2=26.3mL$

Therefore, the final volume of gas will be, 26.3 mL

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