Question

1.* Write the name and symbol of the ion formed when

Answer 1

Answer:

Explanation:

1.  

a. When a sulphur atom gains two electrons, it becomes negatively charged to form an anion called sulphide ion and it’s represented as S2-.  

b. When an aluminium atom loses three electrons, it becomes positively charged to form a cation and it is represented as Al3+.  

c. When a nitrogen atom gains three electrons, it becomes negatively charged to form an anion called nitride ion and it is represented as N3-.  

d. When a calcium atom loses two electrons, it becomes positively charged to form a cation and it is represented as Ca2+  

2.  

• When Iron (Fe) loses two electrons, it becomes Fe2+ and the electronic configuration will be 1S2 2S2 2P6 3S2 3P6 3d6  

• When Cobalt (Co) loses two electrons, it becomes Co2+ and the electronic configuration will be 1S2 2S2 2P6 3S2 3P6 3d7  

• When Nickel (Ni) loses two electrons, it becomes Ni2+ and the electronic configuration will be 1S2 2S2 2P6 3S2 3P6 3d8  

3.  

•When Chromium (Cr) loses three electrons, it becomes  Cr3+ and the electronic configuration will be 1S2 2S2 2P6 3S2 3P6 3d3

• When Manganese (Mn) loses three electrons, it becomes Mn3+ and the electronic configuration will be 1S2 2S2 2P6 3S2 3P6 3d4  

4.  

•Bromine (Br) gains an electron to become Br-  

•Hydrogen (H) gains an electron to become H-  

•Arsenic (As) gains three electrons to become As3-  

•Selenium (Se) gains two electrons to become Se2-  

Answer 2

1a) anion and S-2
1b) cation and Al+3
1c) anion and N-3
1d) cation and Ca+2