Answer:
Explanation:
1.
a. When a sulphur atom gains two electrons, it becomes negatively charged to form an anion called sulphide ion and it’s represented as S2-.
b. When an aluminium atom loses three electrons, it becomes positively charged to form a cation and it is represented as Al3+.
c. When a nitrogen atom gains three electrons, it becomes negatively charged to form an anion called nitride ion and it is represented as N3-.
d. When a calcium atom loses two electrons, it becomes positively charged to form a cation and it is represented as Ca2+
2.
• When Iron (Fe) loses two electrons, it becomes Fe2+ and the electronic configuration will be 1S2 2S2 2P6 3S2 3P6 3d6
• When Cobalt (Co) loses two electrons, it becomes Co2+ and the electronic configuration will be 1S2 2S2 2P6 3S2 3P6 3d7
• When Nickel (Ni) loses two electrons, it becomes Ni2+ and the electronic configuration will be 1S2 2S2 2P6 3S2 3P6 3d8
3.
•When Chromium (Cr) loses three electrons, it becomes Cr3+ and the electronic configuration will be 1S2 2S2 2P6 3S2 3P6 3d3
• When Manganese (Mn) loses three electrons, it becomes Mn3+ and the electronic configuration will be 1S2 2S2 2P6 3S2 3P6 3d4
4.
•Bromine (Br) gains an electron to become Br-
•Hydrogen (H) gains an electron to become H-
•Arsenic (As) gains three electrons to become As3-
•Selenium (Se) gains two electrons to become Se2-
