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konstantin123 [22]
2 years ago
5

5) 3Na2SO4

Chemistry
1 answer:
xenn [34]2 years ago
7 0

Answer:

3Na2SO4

Explanation:

3Na2SO4

# of molecules: 3 moles of Na2SO4 or 3 × 6.22 × 10^23 molecules.

# of elements: 3 elements l

Name of element: = Sodium, S = Sulphur, O = Oxygen

# of atoms: Na = 6 atoms, S= 3, O= 12

Total # of atoms: 21

The #3 is a Coefficient.

Please mark branliest if you are satisfied. Thanking in anticipation.

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Which structures perform similar functions in plant and animal cells?
lyudmila [28]

Answer:

2

Explanation:

Sorry if Im wrong

8 0
3 years ago
A 30ml sample of a liquid has a mass of 50 grams. What is the density of the liquid?
mash [69]

Answer:

<h2>Density = 1.67 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

Density =  \frac{mass}{volume}

From the question

mass = 50 g

volume = 30 mL

Substitute the values into the above formula and solve for the density

That's

Density =  \frac{50}{30}  \\  =  \frac{5}{3}  \\  = 1.66666...

Wr have the final answer as

<h3>Density = 1.67 g/mL</h3>

Hope this helps you

5 0
3 years ago
Write the balanced reaction and solubility product expression (KSP) for dissolving silver chromate: Ag2CrO4(s). Include all char
Sonbull [250]

Answer:

2Ag⁺ (aq)  + CrO₄⁻² (aq) ⇄  Ag₂CrO₄ (s) ↓

Ksp = [2s]²  . [s] → 4s³

Explanation:

Ag₂CrO₄ → 2Ag⁺  + CrO₄⁻²

Chromate silver is a ionic salt that can be dissociated. When we have a mixture of both ions, we can produce the salt which is a precipitated.

2Ag⁺ (aq)  + CrO₄⁻² (aq) ⇄  Ag₂CrO₄ (s) ↓ Ksp

That's the expression for the precipitation equilibrium.

To determine the solubility product expression, we work with the Ksp

Ag₂CrO₄ (s)  ⇄ 2Ag⁺ (aq)  + CrO₄⁻² (aq)   Ksp

                          2 s                 s

Look the stoichiometry is 1:2, between the salt and the silver.

Ksp = [2s]²  . [s] → 4s³

 

3 0
3 years ago
A gas sample is held at constant temperature. What happens to the pressure of the sample if the volume is doubled and the number
Iteru [2.4K]

Answer:

If the volume is doubled and the number of molecules is doubled, pressure is unchanged

Explanation:

Step 1: Data given

Temperature = constant

Volume will be doubled

Number of molecules will be doubles

Step 2:

p*V = n*R*T

⇒ gas constant and temperature are constant

Initial pressure = n*R*T / V

Initial pressure = 2*R*T/2

Initial pressure =  RT

Final pressure = 4*RT / 4

Final pressure = R*T

If the volume is doubled and the number of molecules is doubled, pressure is unchanged

3 0
3 years ago
Not too sure about this one
Kazeer [188]

Answer:

It should be polarity

8 0
3 years ago
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