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konstantin123 [22]
2 years ago
5

5) 3Na2SO4

Chemistry
1 answer:
xenn [34]2 years ago
7 0

Answer:

3Na2SO4

Explanation:

3Na2SO4

# of molecules: 3 moles of Na2SO4 or 3 × 6.22 × 10^23 molecules.

# of elements: 3 elements l

Name of element: = Sodium, S = Sulphur, O = Oxygen

# of atoms: Na = 6 atoms, S= 3, O= 12

Total # of atoms: 21

The #3 is a Coefficient.

Please mark branliest if you are satisfied. Thanking in anticipation.

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Explanation:

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4 years ago
Gaseous compound Q contains only xenon and oxygen. When a 0.100 g sample of Q is placed in a 50.0-mL steel vessel at 0 C, the pr
Paladinen [302]

The question is incomplete, here is the complete question:

Gaseous compound Q contains only xenon and oxygen. When a 0.100 g sample of Q is placed in a 50.0-mL steel vessel at 0°C, the pressure is 0.230 atm. What is the likely formula of the compound?

A. XeO

B. XeO_4

C. Xe_2O_2

D. Xe_2O_3

E. Xe_3O_2

<u>Answer:</u> The chemical formula of the compound is XeO_4

<u>Explanation:</u>

To calculate the molecular weight of the compound, we use the equation given by ideal gas equation:

PV = nRT

Or,

PV=\frac{w}{M}RT

where,

P = Pressure of the gas = 0.230 atm

V = Volume of the gas  = 50.0 mL = 0.050 L     (Conversion factor:  1 L = 1000 mL)

w = Weight of the gas = 0.100 g

M = Molar mass of gas  = ?

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = Temperature of the gas = 0^oC=273K

Putting value in above equation, we get:

0.230\times 0.050=\frac{0.100}{M}\times 0.0821\times 273\\\\M=\frac{0.100\times 0.0821\times 273}{0.230\times 0.050}=194.9g/mol\approx 195g/mol

The compound having mass as calculated is XeO_4

Hence, the chemical formula of the compound is XeO_4

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4 years ago
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