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kvv77 [185]
3 years ago
13

Ways that charges can be transferred

Physics
2 answers:
Rama09 [41]3 years ago
8 0
Can I have more Details?
sashaice [31]3 years ago
3 0
Friction, Induction, and Conduction
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A particle of mass 73 g and charge 67 µC is released from rest when it is 47 cm from a second particle of charge −25 µC. Determi
stich3 [128]

Answer:

933.804423995 m/s²

Explanation:

q_1 = Charge on particle 1 = 67 µC

q_2 = Charge on particle 2 = -25 µC

r = Distance between the particles = 47 cm

k = Coulomb constant = 8.99\times 10^{9}\ Nm^2/C^2

m = Mass of particle = 73 g

Electric force is given by

F=\dfrac{kq_1q_2}{r^2}\\\Rightarrow F=\dfrac{8.99\times 10^{9}\times -25\times 10^{-6}\times 67\times 10^{-6}}{0.47^2}\\\Rightarrow F=-68.1677229516\ N

The magnitude of force is 68.1677229516 N

Acceleration is given by

a=\dfrac{F}{m}\\\Rightarrow a=\dfrac{68.1677229516}{0.073}\\\Rightarrow a=933.804423995\ m/s^2

The acceleration is 933.804423995 m/s²

8 0
3 years ago
A net force of 50 newtons is applied to a 20 kilogram cart that is already moving at 1 m/s the final speed of the cart was 3 m/s
valina [46]

Answer:

0.8 seconds

Explanation:

F=ma

Let x be the seconds the force is applied.

m = 20kg

F = 50 Newtons (kg*m/sec^2)

acceleration, a, is provided for x seconds to increase the speed from 1 m/s to  3 m/s, an increase of 2m/s

Let's calculate the acceleration of the cart:

F=ma

(50 kg*m/s^2) = (20kg)*a

a = 2.5 m/s^2

---

The acceleration is 2.5 m/s^2.  The cart increases speed by 2.5 m/s every second.  

We want the number of seconds it takes to add 2.0 m/sec to the speed:

(2.5 m/s^2)*x = 2.0 m/s

x = (2.0/2.5) sec

x = 0.8 seconds

7 0
2 years ago
A.) Determine the work done by Zach on the bull.
Lana71 [14]

Explanation:

Work done is a physical quantity that is defined as the force applied to move a body through a particular distance.

Work is only done when the force applied moves a body through a distance.

    Work done  = Force x distance

The maximum work is done when the force is parallel to the distance direction.

The minimum work is done when the force is at an angle of 90° to the distance direction.

 So to solve this problem;

 multiply the force applied by Zack and distance through which the bull was pulled.

3 0
2 years ago
I hope y'all can read this I need help​
Ivanshal [37]

Answer:

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4 0
3 years ago
Plz help
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Cells undergo cell division ( creates more cells to replace dead cells )
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