1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Yuliya22 [10]
3 years ago
11

A resistor and a capacitor are connected in series across an ideal battery having a constant voltage across its terminals. Long

after contact is made with the battery (a) the voltage across the capacitor is A) equal to the battery's terminal voltage. B) less than the battery's terminal voltage, but greater than zero. C) zero. (b) the voltage across the resistor is A) equal to the battery's terminal voltage. B) less than the battery's terminal voltage, but greater than zero. C) zero.
Physics
1 answer:
tino4ka555 [31]3 years ago
4 0

Answer:

A) equal to the battery's terminal voltage.

Explanation:

When the capacitor is fully charged after long hours of charging , its  potential becomes equal to the emf of the battery and its polarity is opposite to that of battery . Hence net emf becomes equal . The capacitor itself becomes a battery which is connected in the circuit with opposite polarity . This results in the net emf and  current becoming zero . There is no charging current when the capacitor is fully charged .

You might be interested in
What is number 14 please tell me
UNO [17]
<span>a thin fibrous cartilage between the surfaces of some joints, e.g., the knee.</span>
3 0
3 years ago
Describe the energy transformation in a flashlight
anastassius [24]

Answer: When the flashlight is turned on, the chemical energy stored in batteries is converted into electrical energy that flows through wires of flashlight. This electrical energy is then transformed into light and heat energies.

Explanation:

4 0
3 years ago
A certain capacitor, in series with a resistor, is being charged. At the end of 10 ms its charge is half the final value. The ti
vichka [17]

To solve this problem we will apply the expression of charge per unit of time in a capacitor with a given resistance. Mathematically said expression is given as

q(t) = e^{-\frac{t}{(R*C)}}

Here,

q = Charge

t = Time

R = Resistance

C = Capacitance

When the charge reach its half value it has passed 10ms, then the equation is,

\frac{1}{2}*q_{final} = e^{-\frac{0.01}{(R*C)}}

Ln(\frac{1}{2}) = -\frac{0.01}{RC}

- RC = \frac{0.01}{Ln(1/2)}

RC = 0.014s

We know that RC is equal to the time constant, then

T = RC  = 0.014s = 14ms

Therefore the time constant for the process is about 14ms

5 0
3 years ago
Radiation, conduction, and convection are methods of energy transfer. Of these methods, radiation is the only one in which energ
UkoKoshka [18]
<span>Space.Energy can pass through the space only by radiation. In space there is no matter, liquids or solids to pass energy. The sunlight passes through space and reach earth and other planets in the form of radiation. Radiation is the transmission of energy in the form of electromagnetic waves which needs no medium.</span>
7 0
3 years ago
Read 2 more answers
a circular loop is hanging on the wall. it has a radius of 33.3 cm and is comprised of 12 coils. there is a magnetic field perpe
Vika [28.1K]

Answer:

I = 2.19A, anticlockwise direction.

Explanation:

Given r = 33cm = 0.33m, N = 12, ΔB = 7.5 - 1.5 = 6.0T, Δt = 3s, R = 3.75Ω

By Faraday's law of electromagnetic induction when there is a change in flux in a coil or loop, an emf is induced in the coil or loop which is proportional to the time rate of change of the magnetic flux through the loop.

The emf E is related to the flux by the formula

E = – NdФ/dt

Where N = number of turns in the coil, Ф = magnetic flux through the loop = BA, B = magnetic field strength, A = Area

In this problem the strength of the magnetic field changes. As a result the flux too changes and an emf is induced in the coil.

So

ΔФ = ΔB×A = ΔB×πr² = 6×π×0.33² = 2.05Wb

E = -NΔФ/Δt = 12×2.05/3 = 8.2V

I = E/R = 8.2/ 3.75 = 2.19A

The direction of the current can be found by pointing the thumb of your right hand in the direction of the magnetic field and curling the remaining fingers around this direction. The direction of the curl of these fingers give the direction of current which in this case is anticlockwise.

5 0
3 years ago
Other questions:
  • This is a model of a Neon atom. How likely is it that this atom would want to bond with another atom? Neon atom Question 5 optio
    7·1 answer
  • What is the displacement of a car with an acceleration of 4.00 m/s2 as it increases.
    11·1 answer
  • An object is moving initially with a velocity of 4.7 m/s . After 3.9 s the object's velocity is -2.1 m/s . What is the object's
    14·1 answer
  • In 1929 Edwin Hubble used a telescope to discover the movement of galaxies. True or false
    12·2 answers
  • Which planet is smaller than Earth’s core?
    5·2 answers
  • Two colours of light which mix to make white light are called
    11·2 answers
  • My school doesn’t really teach help
    14·1 answer
  • Determina la fuerza de acción que se presenta entre dos cuerpo cuyas masas son 500 Kg y 900 Kg, si ambos cuerpos se encuentran s
    13·1 answer
  • The angle of incidence of another red ray is 65º. The refractive index of the glass of block
    7·1 answer
  • How do you find distance from average velocity and time
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!