<h2>Answer:</h2>
No, interference patterns will not be observed as the two sources of light are neither monochromatic neither coherent and therefore interference of light will not form total reinforcement or total cancellation at any point
Answer:
The major transition occurred as a consequence of this change in the universe at this time is that <em>b)The universe became transparent to light for the first time.</em>
Explanation:
For the first 380,000 years or so, the universe was essentially too hot for light to shine. The heat of creation smashed atoms together with enough force to break them up into a dense plasma, an opaque soup of protons, neutrons and electrons that scattered light like fog. Then 380,000 years after the Big Bang, matter cooled enough for atoms to form during the era of recombination, resulting in a transparent, electrically neutral gas.
This set loose the initial flash of light created during the Big Bang, which is detectable today as cosmic microwave background radiation. However, after this point, the universe was plunged into darkness, since no stars or any other bright objects had formed yet.
Answer:
amplitude is 8.92 cm
speed of block is 44.11 cm/s
Explanation:
given data
mass = 0.650 kg
spring constant = 18 N/m
speed = 47 cm/s = 0.44 m/s
speed at x point = 0.350 A
to find out
amplitude of subsequent oscillation
solution
we know here conservation of energy
maximum kinetic energy = maximum potential energy
here we know k is spring constant and m is mass and A is amplitude and v is velocity
so solve it we get
A = 
put here all these value
A = 
A = 0.08931 m
so amplitude is 8.92 cm
and
by conservation of energy
initial energy = final energy
= 
solve we gey V
V = 
put here value Vm = 0.47 , and x = 0.350
V = 
V = 0.4411 m/s
so speed of block is 44.11 cm/s
Answer:
K= 95.4 J
Explanation:
For this exercise we must use the conservation of mechanical energy.
We set a reference system on the floor.
Starting point. Higher
Em₀ = U = m g h
Final point. Just before taking the floor
Em_f = K = ½ m v²
energy is conserved because there is no friction
Em₀ = Em_f
mg h = K
The height is
- h = y -y₀
h = 0- y₀
let's calculate
K = 3.23 (-9.81) (-3.01)
K= 95.4 J
