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Leni [432]
3 years ago
13

(Cr(NH3).](Co(CN)6) is a coordination complex

Physics
1 answer:
never [62]3 years ago
4 0

Answer:19.51%

Explanation:

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Tread design on car B would yield a larger coefficient of static friction between the tires and the road

Explanation:

The car model using the coefficient of static friction doesn't work well with tires. A higher coefficient of static friction would require more force to cause a loss of attraction.

The static frictional force helps to keep the unbanked horizontal turn. This means that the frictional force is the centripetal force.

The tread design of car B ensures that the centripetal force is enough to negotiate the turn. On the other hand, the tread design of car A does not provide the necessary centripetal force, hence car A is unable to negotiate the turn.

Therefore, tread design on car B would yield a larger coefficient of static friction between the tires and the road.

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4 years ago
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Electricity passes through it
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