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2 years ago

50 points

Mathematics

1 answer:

Leya [2.2K]2 years ago

5 0

Answer:

$\frac{2}{4} inch$

Step-by-step explanation:

Step 1

List the length of the wingspan of the five butterflies

$\frac{1}{4}, \frac{1}{4}, 1, \frac{2}{4}, \frac{3}{4}$

Step 2:

The two butterflies with the shortest wingspan has a wing length of $\frac{1}{4}$ inches each.

Step 3:

Total length of the wingspan of the two butterflies with the shortest wingspan

= $=\frac{1}{4} +\frac{1}{4} \\
 = \frac{2}{4}$

Final answer:

= $\frac{2}{4} inch$

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Answer:

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Step-by-step explanation:

Consider the provided matrix.

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$x(t)=c_1v_1e^{\lambda_1t}+c_2v_2e^{\lambda_2t}$

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$x(t)=\begin{bmatrix}-3c_1e^{4t}-c_2e^{2t}\\c_1e^{4t}+c_2e^{2t} \end{bmatrix}$

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Therefore, $c_1=2.5,c_2=1.5$

Thus, the general solution of the equation $x'=Ax$

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$x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}$

The required position of the particle at time t is: $x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}$

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Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

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